Answer:
Port r is 100° from Port p and 26km from Port p
Step-by-step explanation:
Lets note the dimension.
From p to q = 15 km = a
From q to r = 20 km= b
Angle at q = 50° + 45°
Angle at q = 95°
Ley the unknown distance be x
Distance from p to r is the unknown.
The formula to be applied is
X²= a²+ b² - 2abcosx
X²= 15² + 20² - 2(15)(20)cos95
X²= 225+400-(-52.29)
X²= 677.29
X= 26.02
X is approximately 26 km
To know it's direction from p
20/sin p = 26/sin 95
Sin p= 20/26 * sin 95
Sin p = 0.7663
P= 50°
So port r is (50+50)° from Port p
And 26 km far from p
I'm assuming this is a system of equations you want solved so,
x = -y + 3
-2(-y+3)+4y = 6
2y - 6 + 4y = 6
6y = 12
y = 2
x + 2 = 3
x = -1
(-1,2)
Answer:
39 ft²
Step-by-step explanation:
11 ft × 3 ft = 33 ft²
2 ft × 3 ft = 6 ft²
33 ft² + 6 ft² = 39 ft²
Step-by-step explanation:
if the two integers are x and y
xy=-10
x+y=-9
x+(-10/x)=-9
x2+9x-10=0
(x-1)(x+10)=0
x=1 or x=-10
if x=1, y=-10
if x=-10, y=1
so the two integers are 1 and -10
