You can do the box method, multiply them. Then combine like terms.
You can also use the foil method.
f(x) = tan2(x) + (√3 - 1)[tan(x)] - √3 = 0
tan2(x) + √3[tan(x)] - tan(x) - √3 = 0
Factor into
[-1 + tan(x)]*[√3 + tan(x)] = 0
which means
[-1 + tan(x)] = 0 and/or [√3 + tan(x)] = 0
Then
tan(x) = 1
tan-1(1) = pi/4 radians
For the other equation
[√3 + tan(x)] = 0
tan(x) = -√3
tan-1(-√3) = -pi/3
so that
x = pi/4 or -pi/3 in the interval [0, 2pi]
If the closing price on Thursday was 25.69...and the closing price on Wednesday went down -0.75.....then it went down -0.75 to get to 25.69.
so the closing price on Wednesday was : 25.69 + 0.75 = 26.44 <==
Answer: 0.2872
Step-by-step explanation:
Given : In a sample of 1000 randomly selected consumers who had opportunities to send in a rebate claim form after purchasing a product, 260 of these people said they never did so.
i.e. n= 1000 and x= 260
⇒ Sample proportion : 
z-value for 95% confidence interval : 
Now, an upper confidence bound at the 95% confidence level for the true proportion of such consumers who never apply for a rebate. :-



∴ An upper confidence bound at the 95% confidence level for the true proportion of such consumers who never apply for a rebate : 0.2872
Answer is Yes, both congruent by SAS