Which type of stress is shown in the image?

Biology

2 answers:

devlian [24]3 years ago

4 0

Answer:

Tension stress

Explanation:

Tensional stress is the stress that tends to pull something apart. It is the stress component perpendicular to a given surface, such as a fault plane, that results from forces applied perpendicular to the surface or from remote forces transmitted through the surrounding rock.

Fiesta28 [93]3 years ago

3 0

Answer:

shear stress

Explanation:

thats what i put

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There are no known motor proteins that move on intermediate filaments (IFs).

Harlamova29_29 [7]

Answer: The correct option is E ( Intermediate filaments are unpolarized).

Explanation:

Intermediate Filaments are usually associated with cells that can withstand mechanical stress which includes claws of animals, hair and makes up the dead remnants of the epidermal cell of the skin. Therefore without the supporting network of intermediate filaments, an epithelium remains intact but the cells are prone to damage by abrasive forces.

Intermediate filaments are so named because they are thicker than actin filaments and thinner than microtubules or muscle myosin filaments

The properties or characteristics of an intermediate filaments that explains the lack of motor proteins is as a result of its subunits which are elongated, not globular and are associated in an anti-polar manner. Therefore, the overall filament has no polarity, and therefore no motor proteins move along intermediate filaments

5 0

3 years ago

Glucose-6-phosphate dehydrogenase deficiency (G6PD) is inherited as an X-linked recessive gene 43) in humans. A woman whose fath

LiRa [457]

Answer:

50% or 1/2. The result remains unchanged if the husband were to have G6PD.

Explanation:

For X-linked recessive inheritance, a female (XX) needs two recessive alleles to be affected while a male needs only one (XY). It is hypothetically assumed that the Y chromosome does not carry any trait.

Assuming the allele for the disease is represented by g, a woman whose father suffered from G6PD is a carrier for the disease with genotype $X^GX^g$ . A normal man will have the genotype $X^GY$ . When the 2 marries:

$X^GX^g$ x $X^GY$ = $X^GX^G (normal female), X^GY (normal male), X^GX^g (carrier female), X^gY (affected male)$ It thus means that 50% or 1/2 of their sons will be expected to have G6PD.

Now, assuming the husband has G6PD, the mating becomes:

$X^GX^g$ x $X^gY$ = $X^GX^g (carrier female), X^GY (normal male), X^gX^g (affected female), X^gY (affected male)$ 50% or 1/2 of their sons is still expected to have G6PD. The ratio remains unchanged.