John is making a tent for the next camping trip. The tent is pictured below. How

Deon bought 26 pounds of rice for $11 . how many pounds of rice did he get per dollar?

ivanzaharov [21]

For $11, he bought = 26 pounds
so, for 1, it would be: 26/11 = 2.36

In short, Your Answer would be 2.36

Hope this helps!

5 0

3 years ago

A coin is flipped until 3 heads in succession occur. list only those elements of the sample space that require 6 or less tosses.

Mashutka [201]

we are given

A coin is flipped until 3 heads in succession occur

so, firstly, we will find sample space

S={HHH , THHH , HTHHH, TTHHH , TTTHHH , HTTHHH , THTHHH , HHTHHHH, ......}

now, we are given that

list only those elements of the sample space that require 6 or less tosses

so, we can see that sample space

S={HHH , THHH , HTHHH, TTHHH , TTTHHH , HTTHHH , THTHHH , HHTHHHH, ......}

There are infinite such possibilities

so, there are infinite number of elements in space

and we know that

discrete sample space will always have finite elements

but we have infinite number of sample space elements here

so, this is not discrete sample space...........Answer

6 0

3 years ago

You have total coins for a total of $. . You only have quarters and dimes. Let represent the number of quarters and represent th

Sonja [21]

Answer:

$Quarters = 41$

$Dimes = 18$

Step-by-step explanation:

Given

$Coins = 59$

$Worth = \$12.05$

$d = dimes$

$q = quarters$

Required

The number of each coin

The total coins can be represented as:

$d + q = 59$

$1\ quarter = \$0.25 \\ 1\ dime = \$0.10$

So, the worth of the coin is:

$0.25q + 0.10d = 12.05$

The equations to solve are:

$0.25q + 0.10d = 12.05$

$d + q = 59$

Make d the subject in: $d + q = 59$

$d =59 - q$

Substitute $d =59 - q$ in $0.25q + 0.10d = 12.05$

$0.25q + 0.10(59 - q) = 12.05$

$0.25q + 5.9 - 0.10q = 12.05$

Collect like terms

$0.25q - 0.10q = 12.05 - 5.9$

$0.15q = 6.15$

Solve for q

$q=\frac{6.15}{0.15}$

$q=41$

Substitute $q=41$ in $d =59 - q$

$d = 59 - 41$

$d = 18$

So:

$Quarters = 41$

$Dimes = 18$

5 0

3 years ago

A marketing researcher wants to find a 96% confidence interval for the mean amount those visitors spend per person per day while

ki77a [65]

Answer:

$n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38$

So then the minimum sample to ensure the condition given is n= 38

Step-by-step explanation:

Notation

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=12$ represent the population standard deviation

n represent the sample size

ME = 4 the margin of error desired

Solution to the problem

When we create a confidence interval for the mean the margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =4 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 96% of confidence interval now can be founded using the normal distribution. The significance is $\alpha=1-0.96 =0.04$ . And in excel we can use this formula to find it:"=-NORM.INV(0.02;0;1)", and we got $z_{\alpha/2}=2.054$ , replacing into formula (b) we got:

$n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38$

So then the minimum sample to ensure the condition given is n= 38

5 0

3 years ago

Determine the distance between point A(-3,7) and the line y = 1/3x-2.

nika2105 [10]

hmmmm i think there is another part of this

8 0

3 years ago