6.) Which of the following describes the possible solutions to the following inequality?

HELP....my last photo didn't work does this one?

svlad2 [7]

Yes
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6 0

3 years ago

How do I simplify (2k ^2 +5k-6) (3k-1)

wolverine [178]

(2k² + 5k - 6)(3k - 1)
(6k³ - 2k² + 15k² - 5k - 18k + 6)
6k² + 13k² - 23k + 6

Use the FOIL method to simplify the problem.
(FOIL stands for first outer, inner, last)

8 0

3 years ago

ANSWER ALL 5 PARTS.

N76 [4]

A function $f$ from a set A to a set B is defined as a relation that assings to each element $x$ in the set A exactly one element $y$ in the set B. The set A is called the domain of the function while the set B is the range. So we have five statements and need to find some functions. Melissa decides to reserve a patch in her vegetable garden for growing bell peppers. If each side of the tomato patch is $x$ feet, then we have a square patch as shown in the Figure below.

1.a) Write the function Wa(x) representing the width of the bell pepper patch.

We know that she wants its width to be half the width of the tomato patch. Let $x$ be the width of the tomato patch, then the function that matches this statement is:

$\boxed{Wa(x)=\frac{x}{2}}$

1.b) Write the function La(x) representing the length of the bell pepper patch.

In this case Melissa wants its length to exceed the length of the tomato patch by 2 feet. To do this we enlarge the length of the tomato patch 2 feet. Therefore the function is the following:

 $\boxed{La(x)=x+2}$

2. Area of the bell pepper patch in terms of x.

Given that the bell pepper patch is a rectangle, then the area of a rectangle is the product of the length and width. So:

 $A=(\frac{x}{2})(x+2) \\ \\ \therefore \boxed{A=\frac{x(x+2)}{2}}$

3. Combined area of the tomato patch and the bell pepper patch.

This function is the sum of both the area of the tomato patch and the bell pepper patch. So:

 $Aar(x)=x^{2}+\frac{x(x+2)}{2} \rightarrow Aar(x)=x^{2}+ \frac{x^{2}}{2}+x \rightarrow Aar(x)=\frac{3x^{2}}{2}+x \\ \\ \therefore \boxed{Aar(x)=\frac{x(3x+2)}{2}}$

4. Write the function Aa(x) for the remaining planting area in the garden.

The remaining planting area in the garden are the rectangles in red. So we need to subtract the width of the bell pepper patch from the width of the tomato patch and multiply it by 2. In mathematical language this is given by:

 $Aa(x)=2(x-\frac{x}{2}) \rightarrow Aa(x)=x$

5. Find the area of the remaining space in the garden after planting tomatoes and bell peppers.

Given that Melissa wants the area of the bell pepper patch to be 31.5 square feet, then it is true that:

 $31.5=\frac{x(x+2)}{2} \rightarrow x^{2}+2x-64=0 \\ \\ solving \ for \ x: \\ x=7.06$

Therefore the area of the remaining space is:

 $\boxed{Aa(7.06)=7.06ft^{2}}$

6 0

3 years ago

Ming has a standard 52-card deck. A standard 52-card deck has 4 suits (♠, ♣,♦, and ♥) and an equal number of cards of each suit.

soldier1979 [14.2K]

Answer:

Option D.

Step-by-step explanation:

Total number of cards = 52

Total number of cards of each suit (♠, ♣,♦, and ♥) = 13

The probability of getting a card of heart is

$\text{Probability of getting a card of heart}=\frac{\text{Number of heart cards}}{\text{Total number of cards}}$

$\text{Probability of getting a card of heart}=\frac{13}{52}$

$\text{Probability of getting a card of heart}=\frac{1}{4}$

The probability of getting a card other then heart is

$1-\frac{1}{4}=\frac{3}{4}$

If Ming randomly draw a card from the deck 300 times, putting the card back in the deck after each draw, then the number of cards she will draw something other than a heart is

$300\times \frac{3}{4}=225$

Close to 225 times but probably not exactly 225 times.

Therefore, the correct option is D.

3 0

3 years ago

What are the x- and y- coordinates of point P on the directed line segment from A to B such that P is the length of the line seg

erica [24]

Answer:

the correct answer is (-1, 2)

Step-by-step explanation:

4 0

3 years ago