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sergey [27]
2 years ago
7

If someone could help me answer this and possibly give me a step-by-step for future reference that'd be great thanks.

Mathematics
1 answer:
andreyandreev [35.5K]2 years ago
6 0

Answer:

Let's look at the Venn diagram and the data we have:

There are 12 pupils

9 have a brother

7 have a sister

2 have neither.

Now let's look at the diagram.

We know that the circle B represents the pupils who have a brother

Circle S represents the students that have a sister.

Then the intersection of the circles, represents the number of students that have both.

And the space outside the circles represents the pupils that do not have a brother nor a sister.

Then the first thing we can complete is a 2 in the bottom left corner, because we already know that there are 2 pupils that do not have brothers nor sisters.

Now let's find the number of students that have both, brothers and sisters:

There are 12 pupils.

9 have a brother

7 have a sister

2 have neither

if we add that, we get:

9 + 7 + 2 = 18

This is larger than 12, this means that we are counting some of the students more than once.

If X is the number of students that we are counting twice, we should have:

18 - X  = 12

18 -12 = X = 6

There are 6 students who we are counting twice, and this happens because these 6 students have a brother and a sister.

Then in the intersection of both circles we should put a 6.

At the left of that (in the part that we have only circle B) we need to write the number of students that only have a brother, this is the number of students that have a brother minus the number of pupils that have a brother and a sister, this is:

9 - 6 = 3

We need to write a 3 in that square.

And in the last square (the one that is only one circle S) we need to write the number of pupils that only have a sister, this is calculated in the same way than before, this is:

7 - 6 = 1

We need to write a 1 in the rightmost square.  

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max2010maxim [7]

Answer:

\sqrt{400 \times 400 - 24 \times 400 - 360 \times 400 - 200} \\  \\  = \sqrt{160000 - 9600 - 144000 - 200} \\  \\  = \sqrt{160000 - 9600 - 144000 - 200} \\  \\ = \sqrt{160000 - 153,800} \\  \\  = \sqrt{6200} \\  \\  = 78.74 \\  \\

7 0
3 years ago
Evaluate 3x (2+6) divide 4 -2
kondaur [170]

Answer:

4

Step-by-step explanation:

Brackets always mean "DO THIS FIRST!!!"

2+6 = 8

Then, do 3 x 8. That is 24.

24 divided by 4 is 6.

6 - 2 is 4!

8 0
3 years ago
when u do a problem like this- 9+(-8) -does the -8 change to a positive 8 and does it become subtraction bc of the double negati
tekilochka [14]
Changes to a positive

8 0
3 years ago
Read 2 more answers
Solve Y^2 +9y+2=8y+58
KengaRu [80]

Answer:

y²+y-56=0

56=8×7

8-7=1

(y+8)×(y-7)=0

y=7

or

y=-8

so its 7,-8

8 0
2 years ago
Read 2 more answers
On Friday night, Alex ate a large pizza for dinner and had LaTeX: \frac{3}{5}3 5 of the pizza left over when he was done. On Sat
ludmilkaskok [199]

Answer:

Alex ate \frac{3}{10} of the large pizza on Saturday.

Step-by-step explanation:

Given:

Amount of Pizza which was left over on Friday = \frac{3}{5}

Amount of Pizza ate on Saturday  = \frac{1}{2} of the Amount of Pizza was left over on Friday

We need to find how much did Alex eat on Saturday.

Solution;

Since we know that Alex ate on Saturday \frac{1}{2} of the Amount of Pizza which was left over on Friday.

So to find the amount he ate n Saturday we will Multiply \frac{1}{2} with the Amount of Pizza which was left over on Friday.

framing in equation form we get;

Alex ate on Saturday = \frac{1}{2}\times \frac{3}{5}= \frac{3}{10}

Hence Alex ate \frac{3}{10} of the large pizza on Saturday.

4 0
3 years ago
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