Answer:
Rider 1 does one round in 15 min, and will complete another in each consecutive multiple of 15 min
Rider 2 does one round in 18 min, and will complete another in each consecutive multiple of 18 min
Assuming that they start together, they will complete another round together in a time that is both multiples of 15min and 18 min.
Then we need to find the smallest common multiple between 15 and 18.
To smallest common multiple between two numbers, a and b, is equal to:
a*b/(greatest common factor between a and b).
Now, the greatest common factor between 15 and 18 can be found if we write those numbers as a product of prime numbers, such as:
15 = 3*5
18 = 2*3*3
The greatest common factor is 3.
Then the smallest common multiple will be:
(15*18)/3 = 90
This means that after 90 mins, they will meet again at the starting place.
Answer:
Step-by-step explanation:
Given
To find
Solution
- f(19) = 3/(19 + 2) - √(19 - 3) = 3/21 - √16 = 1/7 - 4 = - 27/7
Set up multiplication of ratios so that they cancel out units that you do not need in your final answer...
5lb($4.20/2lb)=$10.50
I’m pretty sure the answer is 12
