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masya89 [10]
2 years ago
10

HELP QUICK PLEASE 12(20 + b)

Mathematics
2 answers:
sweet-ann [11.9K]2 years ago
5 0

Answer:

b+9=20-12

Step-by-step explanation:

Hopefully this helped, if not HMU and I will try my best to get you a better answer!

blsea [12.9K]2 years ago
3 0

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

12(20 + b) =

12 \times (20) + (12) \times b =

240 + 12b

♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️♥️

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Help me pleaseeee!!!
Colt1911 [192]

Answer:

Slope = 3

Step-by-step explanation:

Because it increases by 3 each time.

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3 years ago
What is 7/16 simplified
Georgia [21]
You cant simplify it . it is already simplified 
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A rectangle has length 127.3 cm and width 86.5 cm, both correct to 1 decimal place. Calculate the upperbound and the lowerbound
Mnenie [13.5K]

Answer:

Correct to 1dp

127.3 cm = 127.0 cm

86.5 cm = 87.0 cm

Upper limits:

127.0 cm = 127.05 cm

87.0 cm = 87.05 cm

Lower Limits:

127.0 cm = 126.95 cm

87.0 cm = 86.95 cm

upper limit of perimeter of rectangle:

P = 2(l+w)

= 2(127.05 + 87.05)

= 2(214.1)

= 428.2 cm

lower limit of perimeter of rectangle:

P = 2(l+w)

= 2(126.95 + 86.95)

= 2(213.9)

= 427.8 cm

therefore;

427.8 cm \leqslant perimeter < 428.2cm

8 0
3 years ago
PLEASE ANSWER 100POINTS+BRAINLEST PLEASE HELP NO DUMMY ANSWERS
makkiz [27]
The answer is on google no dumb stuff dummy
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find the work done by a person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long (i
tankabanditka [31]

The work done in pushing the box is 64000 lb-ft²/s²

<h3>How to calculate the work done by the person?</h3>

Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is

W = mgh where

  • m = mass of box = 40 lb,
  • g = acceleration due to gravity = 32 ft/s² and
  • h = height of incline = LsinФ where
  • L = length of incline = 100 ft and
  • Ф = angle of incline = 30°

So, W = mgh

W = mgLsinФ

So, substituting the values of the variables into the equation, we have

W = mgLsinФ

W = 40 lb × 32 ft/s² × 100 ftsin30°

W = 1280 lb-ft/s² × 100 ft × 0.5

W = 1280 lb-ft/s² × 50 ft

W = 64000 lb-ft²/s²

So, the work done in pushing the box is 64000 lb-ft²/s²

Learn more about work done here:

brainly.com/question/25970931

#SPJ1

3 0
1 year ago
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