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Tasya [4]
3 years ago
7

A pyramid has a square base that is 160 m on each side. what is the perimeter in kilometers

Mathematics
2 answers:
Otrada [13]3 years ago
7 0

Keywords:

<em>perimeter, square, base, pyramid, kilometers, side </em>

For this case we must find the perimeter of the base of a square pyramid, whose side of the square measures 160m. In addition, the measure obtained must be converted to kilometers. So, we have by definition the perimeter of a square is the sum of its sides, which is equivalent to P = 4l, where "l" is the side of the square.

Ifl = 160m, then:

P = 4 * 160m\\P = 640m

Thus, the perimeter of the base of the pyramid is 640m.

On the other hand, by definition: 1Km = 1000m

By making a rule of three we have:

1Km ---------> 1000m

x --------------> 640m

Where "x" represents the perimeter of the base of the pyramid in Km.

x = \frac {640 * 1} {1000}\\x = 0.64km

Thus, the perimeter of the base of the pyramid is 0.64Km

Answer:

The perimeter in kilometers is 0.64

11Alexandr11 [23.1K]3 years ago
3 0
<span>1km=1000m 160m=0.160x4=0.64

</span>
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frutty [35]

Answer:

cosФ = \frac{1}{\sqrt{65}} , sinФ = -\frac{8}{\sqrt{65}} , tanФ = -8, secФ = \sqrt{65} , cscФ = -\frac{\sqrt{65}}{8} , cotФ = -\frac{1}{8}

Step-by-step explanation:

If a point (x, y) lies on the terminal side of angle Ф in standard position, then the six trigonometry functions are:

  1. cosФ = \frac{x}{r}
  2. sinФ = \frac{y}{r}
  3. tanФ = \frac{y}{x}
  4. secФ = \frac{r}{x}
  5. cscФ = \frac{r}{y}
  6. cotФ = \frac{x}{y}
  • Where r = \sqrt{x^{2}+y^{2} } (the length of the terminal side from the origin to point (x, y)
  • You should find the quadrant of (x, y) to adjust the sign of each function

∵ Point (1, -8) lies on the terminal side of angle Ф in standard position

∵ x is positive and y is negative

→ That means the point lies on the 4th quadrant

∴ Angle Ф is on the 4th quadrant

∵ In the 4th quadrant cosФ and secФ only have positive values

∴ sinФ, secФ, tanФ, and cotФ have negative values

→ let us find r

∵ r = \sqrt{x^{2}+y^{2} }

∵ x = 1 and y = -8

∴ r = \sqrt{x} \sqrt{(1)^{2}+(-8)^{2}}=\sqrt{1+64}=\sqrt{65}

→ Use the rules above to find the six trigonometric functions of Ф

∵ cosФ = \frac{x}{r}

∴ cosФ = \frac{1}{\sqrt{65}}

∵ sinФ = \frac{y}{r}

∴ sinФ = -\frac{8}{\sqrt{65}}

∵ tanФ = \frac{y}{x}

∴ tanФ = -\frac{8}{1} = -8

∵ secФ = \frac{r}{x}

∴ secФ = \frac{\sqrt{65}}{1} = \sqrt{65}

∵ cscФ = \frac{r}{y}

∴ cscФ = -\frac{\sqrt{65}}{8}

∵ cotФ = \frac{x}{y}

∴ cotФ = -\frac{1}{8}    

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3 years ago
The owner of the Koffee Shop pours the remainder of her old house blend, which is 40 % 40 % Colombian beans, into a 60 60 -pound
maks197457 [2]

Answer:

0.4h ; 60 - h ;18 - 0.3h ; 0.1h + 18

Step-by-step explanation:

Given that:

Old house blend = 40% Columbian beans

New house blend = 30% Columbian beans

h = number of pounds of old house blend

a.) pound of columbian bean in old house blend :

40% of h = 0.4h

b.) pound of new blend poured into the bean:

Size of bin = 60 pound

Size of bin - pound of old house blend

(60 - h)

c. Amount of columbian bean in pound of new house blend :

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D.) Amount of columbian bean in 60 pound bin

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0.4h + 18 - 0.3h

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Hence, the value of x is 1.

<h2>What is length?</h2>

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<h3>How to solve?</h3>

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we know, for congruent triangles, the length of corresponding sides is equal.

Hence,

       AB = DE

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       3x = 3

       x=1

Therefore, the value of x is 1.

to learn more about length: brainly.com/question/18077445

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