Answer:
For a trapezium of height H, parallel side 1 X, and parallel side 2 Y, the area is:
A = (1/2)*H*(X + Y)
with this we can complete the table.
a)
Here we know:
X = 7cm
Y = 11cm
H = 6cm
Then: A = (1/2)*6cm*(7cm + 11cm) = 54 cm^2
b)
Here we know:
X = 8 m
Y = 10 m
A = 126 m^2
Then:
126 m^2 = 0.5*H*(8m + 10m)
126 m^2 = H*9m
126 m^2/9m = H = 14m
Then the height of this trapezoid is 14m
c)
Here we know:
X = 5mm
H = 8mm
A = 72 mm^2
Then:
72 mm^2 = 0.5*8mm*(5mm + Y)
72 mm^2 = 4mm*(5mm + Y)
72mm^2/4mm = 5mm + Y
18 mm = 5mm + Y
18mm - 5mm = Y
13 mm = Y
Then the parallel side 2 is 13 mm long.
<u>Part 1)</u> we have
------> equation A

------> equation B
Substitute the equation B in equation A
![5[12-3y]+2y=16](https://tex.z-dn.net/?f=5%5B12-3y%5D%2B2y%3D16)



Find the value of x
the best approximation is the point 
therefore
<u>the answer Part 1) is the option C</u>

<u>Part 2) </u>we have
------> equation A
------> equation B
equate equation A and equation B



Find the value of y
the solution is the point 
therefore
<u>the answer Part 2) is </u>

A way to add fractions that always works is to multiply each numerator by the denominator of the other, then express the sum of products over the product of the denominators.

Here, you have
The sum is -1 1/12
Answer:
x intercept = 26
y intercept = 6.5
Step-by-step explanation:
n/a