A. 1/3=0.33<br>B. 1/6=0.17<br>C. 1/10=0.10<br>D. 1/4=0.25

Anyone knows how to solve -6(-5x-3)-5x+17?

Rzqust [24]

Combine like terms first (so like the ones that have x with x and someone please help them bc I explained it bad

8 0

3 years ago

Suppose you are conducting a test of significance to try to determine whether your cat, Hope, will go to the correct object (out

ohaa [14]

In this scenario, the parameter is the sample proportion, which is of 0.7.

<h3>What is the parameter?</h3>

When a hypothesis is tested, the parameter is the information obtained from the sample, mean or proportion.

In this case, it is the <em>sample proportion</em>, which is the <u>number of desired outcomes divided by the number of total outcomes</u>.

She goes to the correct object in 70 of those 100 trials, hence:

$p = \frac{70}{100} = 0.7$

The parameter is the sample proportion, which is of 0.7.

You can learn more about sample proportion at brainly.com/question/25868626

4 0

2 years ago

A student has 10 coins in her pocket that have a value of 0.85,The coins are either nickels of dimes. Which system of linear equ

oee [108]

Answer:

p+q = 10...... 1

0.05p+0.10q = 0.85 ..... 2

Step-by-step explanation:

The question is incomplete. Here is the complete question.

A student has 10 coins in her pocket that have a value of $0.85. The coins are either nickels or dimes. If each nickel costs $0.05 and each dime costs $0.10. Which system of linear equations represents this scenario?

Let the number of nickel in the pocket of the student be p

Let the number of dime in the pocket of the student be q

If there are 10 coins in her pocket, then the total coins in her pocket will be represented by the equation;

p+q = 10...... 1

If each nickel costs $0.05, p nickels will cost $0.05×p = $0.05p

If each dime costs $0.10, q nickel will costs $0.10×q = $0.10q

Total amount will be $0.05p+$0.10q

Now if the total coins in her pocket has a value of $0.85, then the we will equate $0.05p+$0.10q to $0.85 to give our second linear equation as:

$0.05p+$0.10q = $0.85 ....... 2

Therefore, the system of linear equations represents this scenario are:

p+q = 10...... 1

0.05p+0.10q = 0.85 ..... 2

7 0

3 years ago

A car whose acceleration is constant reaches a speed of

Sergeu [11.5K]

Answer:

12.5 s

Step-by-step explanation:

If acceleration is constant, speed is proportional to time. To increase the speed by 50 km/h, the car will need an additional time given by ...

t/(50 km/h) = (20 s)/(80 km/h)

t = (20 s)(50/80) . . . . . multiply by 50 km/h

t = 12.5 s

It will take 12.5 more seconds for it to reach a speed of 130 km/h.

3 0

3 years ago

Read 2 more answers

Find the LCM of 3,12,16

maria [59]

Answer:

The lcm is 48. Hope this helps

7 0

3 years ago

Read 2 more answers

A. 1/3=0.33B. 1/6=0.17C. 1/10=0.10D. 1/4=0.25​

A. 1/3=0.33B. 1/6=0.17C. 1/10=0.10D. 1/4=0.25