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ozzi
3 years ago
10

What is the distance between the point (−10, −2)(−10, −2) and the point (−4, −2)(−4, −2) ?

Mathematics
2 answers:
Gnoma [55]3 years ago
4 0
In this case:  x 1 = - 10,  y 1 = - 2;
x 2 = - 4 ,  y 2 = - 2
The distance between the points :
d =  \sqrt{(x 2 - x 1 ) ^{2} + ( y 2 - y 1 ) ^{2} } = \\  =\sqrt{(-4+10) ^{2} +(-2+2) ^{2} } = \\ = \sqrt{6 ^{2}+0 ^{2}  } = \sqrt{36}= 6
Answer: d = 6
inessss [21]3 years ago
3 0

In this case:  x 1 = - 10,  y 1 = - 2;

x 2 = - 4 ,  y 2 = - 2

The distance between the points :

d =  \sqrt{(x 2 - x 1 ) ^{2} + ( y 2 - y 1 ) ^{2} } = \\  =\sqrt{(-4+10) ^{2} +(-2+2) ^{2} } = \\ = \sqrt{6 ^{2}+0 ^{2}  } = \sqrt{36}= 6  

Answer: d = 6

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Since each angle of a rectangle is right-angle, so triangle ABD will be a right-angled triangle.

Using Pythagoras theorem in triangle ABD, we have

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