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3 years ago

What is the distance between the point (−10, −2)(−10, −2) and the point (−4, −2)(−4, −2) ?

2 answers:

4 0

In this case: x 1 = - 10, y 1 = - 2;
x 2 = - 4 , y 2 = - 2
The distance between the points :
$d = \sqrt{(x 2 - x 1 ) ^{2} + ( y 2 - y 1 ) ^{2} } = \\ =\sqrt{(-4+10) ^{2} +(-2+2) ^{2} } = \\ = \sqrt{6 ^{2}+0 ^{2} } = \sqrt{36}= 6$
Answer: d = 6

inessss [21]3 years ago

3 0

In this case: x 1 = - 10, y 1 = - 2;

x 2 = - 4 , y 2 = - 2

The distance between the points :

d = \sqrt{(x 2 - x 1 ) ^{2} + ( y 2 - y 1 ) ^{2} } = \\ =\sqrt{(-4+10) ^{2} +(-2+2) ^{2} } = \\ = \sqrt{6 ^{2}+0 ^{2} } = \sqrt{36}= 6

Answer: d = 6

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Whats the measure of the angles (SHOW YOUR WORK so I can understand)

evablogger [386]

Answer:

Angle DEB: 52

Angle ADB: 30

Angle CBE: 52

Angle BEC: 38

Step-by-step explanation:

Angle DEB = 52 because triangles' angles must add up to 180. Angle ADB is 30 because it is complementary to angle BDE. Angle CBE is 52 because angle BEC is complementary to BED which is 52 degrees to BEC is 38 degrees. since the angles add up to 180, and C is 90, CBE is 52. Finally, BEC is 38 because it is complementary to BED.

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WITCHER [35]

Answer:

The cosine of the angle is: negative

The sine of the angle is: positive

Step-by-step explanation:

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3 years ago

Find the circumference and the area of a circle with diameter equal to 8.6 inches. Use 3.14 for pi

mariarad [96]

Answer: Circumference of circle = 27.004 inches

Area of circle = 58.0586 inches²

Step-by-step explanation:

Diameter of circle = 8.6 inches

Pi ( $\pi$ ) = 3.14

Circumference of circle (With diameter) = $\pi \\$ d ( $\pi$ ×diameter)

= 3.14 × 8.6

= 27.004 inches

Area of circle (With diameter) = $\pi$ $d^{2}$ /4

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= 3.14 × 73.96 / 4

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5 0

3 years ago

Can anybody help me with any of these problems please

Artist 52 [7]

Answer:

Part 9) $x=7$

Part 10) $m\angle Y=92^o$

Part 11) $x=5$

Part 12)

$m\angle 1=60^o$

$m\angle 2=41^o$

$m\angle 3=19^o$

$m\angle 4=41^o$

$m\angle 5=19^o$

Part 13) The measure of each side is 56 units

Part 14)

$x=10/3$

$HI=12\ units$

$HJ=12\ units$

$IJ=38/3\ units$

Part 15)

$x=7$

$m\angle C=41^o$

$m\angle D=41^o$

$m\angle A=98^o$

Step-by-step explanation:

Part 9) we know that

An isosceles triangle has two equal sides and two equal interior angles

The triangle of the problem is an isosceles triangle

Because has two equal sides and two equal angles

Remember

The sum of the interior angles in any triangle must be equal to 180 degrees

$2(8x-4)^o+76^o=180^o$

solve for x

$16x-8+76=180\\16x=180-68\\16x=112\\x=7$

Part 10) we know that

step 1

Solve for x

An isosceles triangle has two equal sides and two equal interior angles

The triangle XYZ of the problem is an isosceles triangle

Because has two equal sides

$m\angle X=m\angle Z$

substitute the given values

$(4x-12)^o=(2x+16)^o$

solve for x

$4x-2x=16+12\\2x=28\\x=14$

Find the measure of angle X

$m\angle X=(4x-12)^o$

substitute the value of x

$m\angle X=(4(14)-12)=44^o$

$m\angle Z=44^o$

step 2

Find the measure of angle Y

Remember

The sum of the interior angles in any triangle must be equal to 180 degrees

$m\angle Y+2(44^o)=180^o$

$m\angle Y=180^o-88^o=92^o$

Part 11) we know that

we know that

An equilateral triangle has three equal sides and three equal interior angles. The measure of each interior angle is 60 degrees

In this problem we have an equilateral triangle

$(14x-10)^o=60^o$

solve for x

$14x=60+10\\14x=70\\x=5$

Part 12)

step 1

Find the measure of angle 1

we know that

An equilateral triangle has three equal sides and three equal interior angles. The measure of each interior angle is 60 degrees

In this problem the triangle WXY is an equilateral triangle

therefore

$m\angle 1=60^o$

step 2

Find the measure of angle 3

we know that

Triangle WZY is an isosceles triangle

$m\angle 3=m\angle 5$

Remember that

The sum of the interior angles in any triangle must be equal to 180 degrees

$m\angle 3+m\angle 5+142^o=180^o$

$2m\angle 3=180^o-142^o$

$m\angle 3=19^o$

$m\angle 5=19^o$

step 3

Find the measure of angle 2

we know that

The measure of each interior angle of an equilateral triangle is equal to 60 degrees

$m\angle 2+m\angle 3=60^o$

substitute the given value

$m\angle 2+19^o=60^o$

$m\angle 2=60^o-19^o$

$m\angle 2=41^o$

step 4

Find the measure of angle 4

we know that

The measure of each interior angle of an equilateral triangle is equal to 60 degrees

$m\angle 4+m\angle 5=60^o$

substitute the given value

$m\angle 4+19^o=60^o$

$m\angle 4=60^o-19^o$

$m\angle 4=41^o$

Part 13) we know that

we know that

An equilateral triangle has three equal sides and three equal interior angles. The measure of each interior angle is 60 degrees

AB=BC=AC

solve the equation

AB=BC

substitute the given values

$5x-9=7x-35\\7x-5x=35-9\\2x=26\\x=13$

Find the measure of side AB

$AB=5x-9$

substitute the value of x

$AB=5(13)-9=56\ units$

Verify BC and AC

$BC=7(13)-35=56\ units$ ----> is correct

$AC=4(13)+4=56\ units$ ----> is correct

Part 14) we know that

An isosceles triangle has two equal sides and two equal angles

In this problem Triangle HIJ is an isosceles triangle

because

Angle I is equal to Angle J

HI=HJ

substitute the given values

$6x-8=3x+2$

solve for x

$6x-3x=2+8\\3x=10\\x=10/3$

Find the measure of each side

$HI=6(10/3) -8=12\ units$

$HJ=3(10/3)+2=12\ units$

$IJ=5(10/3)-4=38/3\ units$

Part 15) we know that

Triangle ACD is an isosceles triangle

because

has two equal sides

AC=AD

$m\angle C=m\angle D$

substitute the given values

$6x-1=7x-8$

solve for x

$7x-6x=8-1\\x=7$

Find the measure of angle C

$m\angle C=6(7)-1=41^o$

Find the measure of angle D

$m\angle D=7(7)-8=41^o$

Find the measure of angle A

we have that

$m\angle C+m\angle D+m\angle A=180^o$

substitute

$41^o+41^o+m\angle A=180^o$

$m\angle A=180^o-82^o$

$m\angle A=98^o$

3 0

3 years ago