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Mathematics

1 answer:

FrozenT [24]3 years ago

7 0

Answer:

The x-intercept is a point on the x-axis where the line crosses the x-axis and you can easily find it at point (-7, 0) because the line crosses the x-axis there.

Similarly, the y-intercept is a point on the y-axis where the line crosses the y-axis and you can easily find it at point (0, 2) because the line crosses the y-axis there.

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Help me please I need it

koban [17]

Unfortunately, you inadvertently cut off the instructions for this problem when you photographed it. Could you try again, making certain to include the instructions?

Let me guess: perhaps the instructions are 1) determine the slope of the line passing through the given points, or 2) write the equation of the line passing through the given points.

5 0

3 years ago

Can someone solve this question?

Rom4ik [11]

The triangles are isosceles. The following notation are for the angles. For example ABD is refer to the angle located in the B vertex, formed by the segments AB and BD.

$ABD = ADB\\40 + 2ADB = 180\\ADB = 70 = ABD\\$

$70 + DBC + 30 = 180\\DBC = 180 - 100 = 80$

Then

$BCD = BCD\\2BCD + 80 = 180\\BCD = 50$

3 0

3 years ago

Can anyone please help

shusha [124]

$\text{Hi there! :)}$

$\large\boxed{f'(2) = -\frac{16}{27} }$

$f'(x) = \frac{(5 + x^{2} )(-2x) - (7 - x^{2} )(2x)}{(5+x^{2})^{2} } \\\\f'(x) = \frac{-10x-2x^{3}- 14x + 2x^{3} }{(5+x^{2})^{2} } \\\\f'(x) = \frac{-24x}{(5+x^{2})^{2} }\\\\ \text{Solve for the derivative at f'(2) using substitution:}\\\\f'(2) = \frac{-24(2)}{(5+2^{2})^{2} } \\\\f'(2) = \frac{-48}{81} \\\\\text{Simplify:}\\\\f'(2) = -\frac{16}{27}$