Question

Determine the zeros of f(x) when n=2. Please help I attached the image

Answer 1

Answer:

x=0 and -2

Notice a n=8, g(n)=0 and f(x) = 0.  If n<8, the coefficients for f(x) become negative and when n>8, the coefficients becomes positive.  It won't affect x=0 because x can be factor out and be equal to zero but will affect the second zero

Step-by-step explanation:

Given:  g(n) = 1/2*n - 4 and f(x)= g(n)x^2 + 2(g(n))x; n≠8

n = 2

g(n) = 1/2*n - 4

g(n) = 1/2*2 - 4 = 1-4 = -3

f(x)= g(n)x^2 + 2(g(n))x

f(x)= -3x^2 + 2(-3)x = -3x^2 - 6x

0=  -3x^2 - 6x; factor out -3x

0 = -3x(x + 2)

-3x = 0; x=0

(x+2)= 0; x=-2

Notice a n=8, g(n)=0 and n<8, the coefficients for f(x) become negative and when n>8, the coefficients becomes positive

Answer 2

Answer:

398.634

Step-by-step

(3x40)200x2b