Given:
Two sides of a triangle are 9 and 5.
To find:
The range of possible measures for the third side.
Solution:
In a triangle, the sum of smaller sides must be greater than the largest side.
Let x be the measure of third side.
Case 1: When x is the largest side, then
...(i)
Case 2: When 9 is the largest side, then
...(ii)
Using (i) and (ii), we get
Therefore, the range of possible measures for the third side is .
Answer: 65
Step-by-step explanation:
<u>Given:</u>
This year's attendence = 107
Let last year's attendence = x
<u>Create an equation an solve for x:</u>
2x - 23 = 107
2x = 107 + 23
2x = 130
x = 130/2
x = 65
Therefore, 65 children attended last year's Vacation Bible School
Answer:
Mateo jogged 8 3/20 miles in the past 2 days.
Step-by-step explanation:
Given:-
Distance on Saturday = 3 3/4
Distance on Sunday = 4 2/5
Total distance = 3 3/4 + 4 2/5
= 15/4 + 22/5
= LCM of deniminators (20)
= 75/20 + 88/20
= (75 + 88)/20
= 163/20
= 8 3/20
Since both statements are true, then it is
contrapositive