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kkurt [141]
3 years ago
11

I need this answered its due soon

Mathematics
1 answer:
mixer [17]3 years ago
7 0
<h2><u>C D E</u></h2>

A is false because this graph doesn't have any relative minimums because it never increases

B is false because this graph never increases

C is true

D is true because the graph never goes below 3, but it's blurry so I might be wrong

E is true because it never stops decreasing and has a domain of all real numbers

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Determine whether the following lines represented by the vector equations below intersect, are parallel, are skew, or are identi
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Answer:

r(t) and s(t) are parallel.

Step-by-step explanation:

Given that :

the  lines represented by the vector equations are:

r(t)=⟨1−t,3+2t,−3t⟩

s(t)=⟨2t,−3−4t,3+6t⟩

The objective is to determine if the following lines represented by the vector equations below intersect, are parallel, are skew, or are identical.

NOTE:

Two lines will be parallel if \dfrac{x_1}{x_2}= \dfrac{y_1}{y_2}= \dfrac{z_1}{z_2}

here;

d_1 = (-1, \ 2, \ -3)

Thus;

r(t) = \dfrac{x-1}{-1} = \dfrac{y-3}{2}=\dfrac{z-0}{-3} = t

d_2 =(2, \ -4, \  +6)

s(t) = \dfrac{x-0}{2} = \dfrac{y+5}{-4}=\dfrac{z-3}{6} = t

∴

\dfrac{d_1}{d_2}= \dfrac{-1}{2} = \dfrac{2}{-4}= \dfrac{-3}{-6}

Hence, we can conclude that r(t) and s(t) are parallel.

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