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sertanlavr [38]
3 years ago
9

Question Which number has a 5 in the hundredths place?

Mathematics
2 answers:
Naily [24]3 years ago
7 0

Answer: This doesn't make sense is there a photo?

Step-by-step explanation:

AURORKA [14]3 years ago
6 0

Answer:

500

Step-by-step explanation:

You might be interested in
Find all zeros of ƒ(x) = 2x^4 – 72x^2. Then determine the multiplicity at each zero. State whether the graph will touch or cross
AleksandrR [38]

Answer: See below

Step-by-step explanation:

<u>To find the factor,</u>

f(x) = 0

\begin{aligned}&2 x^{4}-72 x^{2}=0 \\&2 x^{2}\left(x^{2}-36\right)=0 \\&x^{2}\left(x^{2}-36\right)=0 \\&x \times x \times(x-6) \times(x+6)=0 \\&\mathrm{x}=0,0,6,-6\end{aligned}

<u>So,</u>

x = 0 multiplicity 2

x = -6 multiplicity 1

x = 6 multiplicity 1

For an even multiplicty, the graph touches the x-axis, and for an odd multiplicty, the graph crosses the x-axis

<u>Therefore,</u>

x = 0 multiplicty 2, Touch

x = -6 multiplicty 1, Cross

x = 6 multiplicty 1, Cross

7 0
2 years ago
Sorry to bother but i need help on number five please.
Alex
<span>Round to two decimal places</span>
5 0
3 years ago
Read 2 more answers
What is the value of C? <br><br> 55<br> 70<br> 95<br> 110
Lana71 [14]

Answer:

c°=70°

Step-by-step explanation:

taking that it would be an alternate interior totaling 180°

take the difference: 180°-110°=70°

4 0
3 years ago
In the diagram of RST, which term describes point U?
igomit [66]

Answer:A

Step-by-step explanation:

5 0
4 years ago
Read 2 more answers
Arrange the equations in the correct sequence to rewrite the formula for displacement, , to find a. In the formula, d is displac
OverLord2011 [107]

Answer:

2(d-vt)=-at^2

a=2(d-vt)/t^2

at^2=2(d-vt)

Step-by-step explanation:

Arrange the equations in the correct sequence to rewrite the formula for displacement, d = vt—1/2at^2 to find a. In the formula, d is

displacement, v is final velocity, a is acceleration, and t is time.

Given the formula for calculating the displacement of a body as shown below;

d=vt - 1/2at^2

Where,

d = displacement

v = final velocity

a = acceleration

t = time

To make acceleration(a), the subject of the formula

Subtract vt from both sides of the equation

d=vt - 1/2at^2

d - vt=vt - vt - 1/2at^2

d - vt= -1/2at^2

2(d - vt) = -at^2

Divide both sides by t^2

2(d - vt) / t^2 = -at^2 / t^2

2(d - vt) / t^2 = -a

a= -2(d - vt) / t^2

a=2(vt - d) / t^2

2(vt-d)=at^2

4 0
3 years ago
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