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3 years ago

Solve the equation 6x + 2x - 5= 19 x=? Simplify your answer

Mathematics

1 answer:

SSSSS [86.1K]3 years ago

7 0

Answer:

x = 3

Step-by-step explanation:

6x + 2x - 5= 19

8X -5 = 19

8x = 24

x = 3

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3 years ago

The region bounded by y=(3x)^(1/2), y=3x-6, y=0

Ganezh [65]

Answer:

4.5 sq. units.

Step-by-step explanation:

The given curve is $y = (3x)^{\frac{1}{2} }$

⇒ $y^{2} = 3x$ ...... (1)

This curve passes through (0,0) point.

Now, the straight line is y = 3x - 6 ....... (2)

Now, solving (1) and (2) we get,

$y^{2} - y - 6 = 0$

⇒ (y - 3)(y + 2) = 0

⇒ y = 3 or y = -2

We will consider y = 3.

Now, y = 3x - 6 has zero at x = 2.

Therefor, the required are = $\int\limits^3_0 {(3x)^{\frac{1}{2} } } \, dx - \int\limits^3_2 {(3x - 6)} \, dx$

= $\sqrt{3} [{\frac{x^{\frac{3}{2} } }{\frac{3}{2} } }]^{3} _{0} - [\frac{3x^{2} }{2} - 6x ]^{3} _{2}$

= $[\frac{\sqrt{3}\times 2 \times 3^{\frac{3}{2} } }{3}] - [13.5 - 18 - 6 + 12]$

= 6 - 1.5

= 4.5 sq. units. (Answer)

7 0

3 years ago

Express the equation x = 10 and y = -3 as a linear equation in two variables

34kurt

Answer:

For x = 10:

$x + 0y - 10 = 0$

For y = - 3:

$0x + y + 3 = 0$

Step-by-step Explanation:

Before we start let's recall the formula for the linear equations.

$ax + bx = c$

So first let's solve for x=10:

$x = 10$

Move 10 to the other side.

$x - 10 = 0$

As there is no y given we will simply write 0y.

$x + 0y - 10= 0$

Now let's solve for y=-3:

$y = - 3$

Move -3 to the other side.

$y + 3 = 0$

As there is no x given we will simply write 0x.

$0x + y + 3 = 0$

If this answer helped you, give this answer a heart, rate it and if you could then please mark it brainliest. Thanks!

8 0

2 years ago