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3 years ago

8

PLEASE HELP ME if m<2 =38° , then what is m<1?

1 answer:

balu736 [363]3 years ago

4 0

Answer:

Answer is 142 hope it helps

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Someone please help me with this

WINSTONCH [101]

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<h2>download the app PHOTOMATH and right your solution</h2>

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3 years ago

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34kurt

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60

Step-by-step explanation:

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Rewrite the formula to solve for w. Choose all of the correct formulas.

timofeeve [1]

B , C & D
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4 years ago

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During a 90-day monsoon season, daily rainfall can be modeled by sinusoidal functions. A low of 4 inches of rainfall was recorde

Phoenix [80]

Answer:

$25.4\,days \leq t \leq 34.6\,days$

Step-by-step explanation:

Let consider the following model:

$c(t) = A \cdot \sin \left(\frac{2\pi \cdot t}{T} \right) + \bar c$

The average is given by the following formula:

$\bar c = \frac{c_{min}+c_{max}}{2}$

The maximum value is:

$c_{max} = 2 \cdot \bar c - c_{min}$

$c_{max} = 2\cdot (8\,in) - 4\,in$

$c_{max} = 12\,in$

Amplitude is:

$A = 12\,in - 8\,in$

$A = 4\,in$

The sine function has a periodicity of $2\pi$ , where is minimum is reached at $\theta = \frac{3\pi}{2}$ , when t = 30. The period of the cycle is:

$T = \frac{2\pi}{\frac{3}{2}\pi }\cdot (30)$

$T = 40$

The complete expression is:

$c(t) = 8\,in + 4\,in \cdot \sin \left(\frac{2\pi}{40}\cdot t \right)$

The times associated with $c = 5\,in$ are, respectively:

$8\,in + 4\,in \cdot \sin \left(\frac{2\pi}{40}\cdot t \right) = 5\,in$

$4\,in \cdot \sin \left(\frac{2\pi}{40}\cdot t \right) = -3\,in$

$\sin \left(\frac{2\pi}{40}\cdot t \right) = -0.75$

$t = \frac{40}{2\pi}\cdot \sin^{-1} (-0.75)$

Instants are, respectively:

$t_{1} \approx 25.4\,days$

$t_{2} \approx 34.6\,days$

Period is:

$25.4\,days \leq t \leq 34.6\,days$

8 0

3 years ago

Solve for p.<br> 2(p+ 1) = 24<br> What is the answer?

kicyunya [14]

Answer:

p=11

Step-by-step explanation:

Distribute: 2p+2=24

Subtract 2 from both sides: 2p=22

Divide both sides by 2 (to get p by itself): p=11

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3 years ago

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