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AURORKA [14]
3 years ago
12

Triangle congruence ​

Mathematics
1 answer:
Tju [1.3M]3 years ago
6 0

Answer:

https://www.beatstars.com/yvngstar

Step-by-step explanation: buy 3 beats on their will get you unlimited answers for any grade and any subject for free. :) you welcome        

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Tyrone used 15 centimeters of tape to wrap 5 presents. How many presents did Tyrone wrap if he used 42 centimeters of tape? Assu
Elan Coil [88]

Answer: 14 presents

Step-by-step explanation:

5 presents 42 cm tape

——————I-———————.

15 cm tape 1

= (5x42) /15 = 14 presents

4 0
3 years ago
Which reflection of the point will produce an image at the same time coordinates (0,k)
Anettt [7]
I need more details.
4 0
2 years ago
(4x+1)(3x-7) yup it hurts
musickatia [10]

Answer:

12x^2-25x-7

Step-by-step explanation:

Multiply each term by its counterpart in the parenthesis.

4x*3x and 4x*-7

1*3x and 1*-7

This gives you 12x^2-4x*7+3x-7 when the like terms are combined.

Collect the like terms, which will give you 12x^2-25x-7

7 0
2 years ago
Read 2 more answers
Which of these is NOT a terminating decimal?<br> A) 1.88<br> B) 1.875 <br> C) 0.88<br> D) 0.8
slamgirl [31]

Answer:

D

Step-by-step explanation:

8 0
2 years ago
You have just isolated a new radioactive element. If you can determine its half-life, you will win the Nobel Prize in physics. Y
Troyanec [42]
Staals half
1 gram left
0.3 grams left
half lives are normally written in years
it goes likt this

A=P( \frac{1}{2})^ \frac{t}{h}
A=final amount
P=initila amount
t=time elapsed
h=time half life is (same units as time)

let's use days as the units of time


we are given
initial amount=1gram
final amount=0.3gram
time=4 days

so
0.3=1( \frac{1}{2})^ \frac{4}{h}
solve for h
0.3=( \frac{1}{2})^ \frac{4}{h}
take the ln of both sides
ln(0.3)=ln( \frac{1}{2})^ \frac{4}{h}
ln(0.3)=\frac{4}{h}ln( \frac{1}{2})
times both sides by h
hln(0.3)=4ln( \frac{1}{2})
divide both sides by ln(0.3)
h= \frac{4ln( \frac{1}{2}) }{ln(0.3)}
use calculator
h=2.30287
3 sig figs
h=2.303 days
6 0
3 years ago
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