We are given with the variable cost which is:
q = -20s + 400
The selling price is 's'. So, the profit can be represented by:
P = qs - q(12)
Subsituting:
P = (-20s + 400)s - 12 (-20s + 400)
P = -20s^2 + 640s - 4800
To optimize this, we must differentiate the equation and equate it to zero, so:\
dP/ds = -40s + 640 = 0
Solving for s,
s = 16
So, the selling price should be $16 to optimize the yearly profit.
Answer:
(x-5)^3
Step-by-step explanation:
(x-5)^3. (x−5)3 ( x - 5 ) 3
Answer:
238.65
Step-by-step explanation:
To find the simple interest we use the formula:
A = P(1 + rt)
Let's break down all the variables that we have.
P = 3,700
r = 2.15% or 0.0215
t = 3
So let's put all our variables into the formula.
A = P(1 + rt)
A = 3,700(1 + (0.0215)(3))
A = 3,700(1 + 0.0645)
A = 3,700(1.0645)
A = 3938.65
Gary will have a total of 3938.65 in his account after 3 years. Now to find how much he made in interest, we simply subtract the total after 3 years to his initial amount.
Interest = 3938.65 - 3700
Interest = 238.65
Step-by-step explanation:
Here we can see the both numbers are 7 with different powers so we can sum up the powers
