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Aleonysh [2.5K]
4 years ago
6

1/3 cup serving contains how much grams

Mathematics
1 answer:
Free_Kalibri [48]4 years ago
3 0
43grams are in 1/3 of a cup
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Answer:

ok just did now give be brainlyest

Step-by-step explanation:

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3 years ago
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A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. ​(a) Describe the
Ivanshal [37]

Answer:

a) \bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 83

\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3

b) z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2

P(Z>2) = 1-P(Z

c) z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45

P(Z

d) z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1

z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2

P(-1.2

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

\mu = 83, \sigma = 27

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})

With:

\mu_{\bar X}= 83

\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3

Part b

We want this probability:

P(\bar X>89)

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 89 we got:

z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2

P(Z>2) = 1-P(Z

Part c

P(\bar X

We can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And if we find the z score for 75.65 we got:

z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45

P(Z

Part d

We want this probability:

P(79.4 < \bar X < 89.3)

We find the z scores:

z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1

z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2

P(-1.2

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3 years ago
The legs of a right triangle are 3 units and 8 units. What is the length of the hypotenuse? Round your answer to the nearest hun
ASHA 777 [7]

Answer:

Step-by-step explanation:

Hypotenuse^2=3^2+8^2

Hypotenuse^2=9+64=73

Hypotenuse =square root of 73

Hypptenuse =8.54

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Write 0.01 as a fraction<br><br> a. 1 1/10<br> b. 1/10<br> c. 1/100<br> d. 1
Lady_Fox [76]
C. 01/100.    .01 is in the hundredths place. So you put 2 0's on the denominator.
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What is the probability that 1 or 2 are rolled on a number cube with sides numbered 1, 2, 3, 4,
choli [55]

Answer: \frac{1}{3}

Step-by-step explanation:

total sides = 6

p (rolling a 1) = \frac{1}{6}

p (rolling a 2) = \frac{1}{6\\}

Note:

or - add

and - multiply

∴ \frac{1}{6} +\frac{1}{6} = \frac{2}{6}

∴ \frac{2}{6} = \frac{1}{3}

hence, p (rolling a 1 or 2) = \frac{1}{3}

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3 years ago
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