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solong [7]
3 years ago
9

Find the perimeter of a triangle with sides measuring 3 centimeters 4 centimeters and 5 centimeters

Mathematics
1 answer:
uranmaximum [27]3 years ago
3 0

Answer:

12 centimeters

Step-by-step explanation:

3+4+5=12

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4 years ago
Write the standard form of the line that passes through the given points.
serious [3.7K]

First of all, remember what the equation of a line is:

<span>y = mx+b

</span>First, let's find what <span>m:
m =   1-(-3) / 2-(-1)
m = 4/3
</span>
so: y = 4/3x + b

Now, what about b, or the y-intercept?

<span>To find b, think about what your (x,y) points mean:
<span><span>(-1,-3).
When x of the line is -1, y of the line must be -3.
</span><span>(2,1).
When x of the line is 2, y of the line must be 1.
</span></span>
Now, look at our line's equation so far: <span>y=4/3x+b</span>. 

You can plug either (x,y) point you want into the x and y variables..the answer will be the same:
<span><span>(-1,-3)
 -3=4/3 × -1+b,
b=-3-(4/3)(-1)
b=-5/3
</span><span>
(2,1)
1=4/3 × 2+b
b=1-(4/3)(2).
b=-5/3.
</span></span>In both cases we got the same value for b.
</span>
So we have y = 4/3x -(5/3).

In standard form it would be:
(4/3)x - y = (5/3)

6 0
3 years ago
Audreys Candy Store sold 22 individual pounds of jelly beans, one kind at $3.87 per pound and the other at $0.94 per pound. In a
slega [8]

Answer:

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  • 19 pounds at $0.94

Step-by-step explanation:

Let x represent the number of pounds of high-priced jelly beans sold. Then the total revenue was ...

  3.87x + 0.94(22 -x) = 29.47

  2.93x + 20.68 = 29.47 . . . . . . eliminate parentheses, collect terms

  2.93x = 8.79 . . . . . . . . . . . . . .  subtract 20.68

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3 pounds of $3.87 jelly beans were sold; 19 pounds of $0.94 jelly beans were sold.

8 0
4 years ago
Enlarge the triangle by scale fador 3 using the blue det<br> as the centre of enlargement
DochEvi [55]

Answer:

Step-by-step explanation:

Let the blue point is located at the origin.

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Rule for the dilation of a point (x, y) by a scale factor 'k' will be,

(x, y) → (kx, ky)

By applying this rule, coordinates of the image points of the vertices will be,

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          → A'(6, 3) for (k = 3)

B(2, -1) → B'(6, -3)

C(3, -1) →C'(9, -3)

7 0
3 years ago
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