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xxMikexx [17]
2 years ago
6

When reflecting a figure across the x-axis, why does the y-value always change signs?

Mathematics
1 answer:
kati45 [8]2 years ago
7 0

Answer:

see description

Step-by-step explanation:

When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is transformed into its opposite (its sign is changed). Notice that B is 5 horizontal units to the right of the y-axis, and B' is 5 horizontal units to the left of the y-axis.

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Answer:

the answer is B:14 inches

Step-by-step explanation:

because 52x14=728

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Please answer all for brainlest and thanks !!! I'm begging :((
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You can find a unit rate when given a rate by dividing the the second number in the rate (if you had 3:4, you would divide 4) by the same number. (in the problem I gave you, you would divide 4 by 4 to get 1 then divide 3 by 4.) Then you would have the unit rate. Sorry if that didn't make any sense.
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Erika is working on solving the exponential equation 50x = 17; however, she is not quite sure where to start. using complete sen
Kryger [21]

Erika is working on solving the exponential equation 50^x = 17; The solution is x = 0.7242.

<h3>What is logarithm?</h3>

When you raise a number with an exponent, there comes a result.

Let's say you get

a^b = c

Then, you can write 'b' in terms of 'a' and 'c' using a logarithm as follows

b = \log_a(c)

'a' is called base of this log function. We say that 'b' is the logarithm of 'c' to base 'a'

Erika is working on solving the exponential equation 50^x = 17;

however, she is not quite sure where to start.

The equation is

50^x = 17\\

By taking the log both sides

log_a b = x\\\\a_x = b

By using the base formula

log_0 y = \dfrac{logy}{log b}

So, log_{50} 17= x\\\\

x = \dfrac{log17}{log 50}

x = 0.7242

Learn more about logarithm here:

brainly.com/question/20835449

#SPJ1

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2 years ago
What is the explicit formula for this sequence? 2, 10, 50, 250, 1250, …
borishaifa [10]

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3 years ago
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PLEASE HURRY IM TIMED!!!
andriy [413]

<u>Answer-</u>

<em>A. Brandon’s sound intensity level is 1/4th as compared to Ahmad’s.</em>

<u>Solution-</u>

Given that, loudness measured in dB is

L=10\log \frac{I}{I_0}

Where,

I   = Sound intensity,

I₀ = 10⁻¹² and is the least intense sound a human ear can hear

Given in the question,

I₁ = Intensity at Brandon's = 10⁻¹⁰

I₂ = Intensity at Ahmad's  = 10⁻⁴

Then,

L_1=10\log \frac{I_1}{I_0}=10\log \frac{10^{-10}}{10^{-12}}=10\log \frac{1}{10^{-2}}=10\log 10^{2}=2\times10\log 10=20

L_2=10\log \frac{I_2}{I_0}=10\log \frac{10^{-4}}{10^{-12}}=10\log \frac{1}{10^{-8}}=10\log 10^{8}=8\times10\log 10=80

\therefore \frac{L_1}{L_2} =\frac{20}{80} =\frac{1}{4}

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3 years ago
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