Answer:
D
Step-by-step explanation:
Answer:
(160, 36)
Step-by-step explanation:
Distance is always positive because, well, you aren't -50 meters away from your house or something. You are just 50 meters away from your house. And 160 is the distance between -6 and 154, because there is one minus and one plus, you add them, because that is how far they are apart, and then-43 and -7 were easy just subtract them.
Answer:
the time taken for the radioactive element to decay to 1 g is 304.8 s.
Step-by-step explanation:
Given;
half-life of the given Dubnium = 34 s
initial mass of the given Dubnium, m₀ = 500 grams
final mass of the element, mf = 1 g
The time taken for the radioactive element to decay to its final mass is calculated as follows;
![1 = 500 (0.5)^{\frac{t}{34}} \\\\\frac{1}{500} = (0.5)^{\frac{t}{34}}\\\\log(\frac{1}{500}) = log [(0.5)^{\frac{t}{34}}]\\\\log(\frac{1}{500}) = \frac{t}{34} log(0.5)\\\\-2.699 = \frac{t}{34} (-0.301)\\\\t = \frac{2.699 \times 34}{0.301} \\\\t = 304.8 \ s](https://tex.z-dn.net/?f=1%20%3D%20500%20%280.5%29%5E%7B%5Cfrac%7Bt%7D%7B34%7D%7D%20%5C%5C%5C%5C%5Cfrac%7B1%7D%7B500%7D%20%3D%20%20%280.5%29%5E%7B%5Cfrac%7Bt%7D%7B34%7D%7D%5C%5C%5C%5Clog%28%5Cfrac%7B1%7D%7B500%7D%29%20%3D%20log%20%5B%280.5%29%5E%7B%5Cfrac%7Bt%7D%7B34%7D%7D%5D%5C%5C%5C%5Clog%28%5Cfrac%7B1%7D%7B500%7D%29%20%20%3D%20%5Cfrac%7Bt%7D%7B34%7D%20log%280.5%29%5C%5C%5C%5C-2.699%20%3D%20%5Cfrac%7Bt%7D%7B34%7D%20%28-0.301%29%5C%5C%5C%5Ct%20%3D%20%5Cfrac%7B2.699%20%5Ctimes%2034%7D%7B0.301%7D%20%5C%5C%5C%5Ct%20%3D%20304.8%20%5C%20s)
Therefore, the time taken for the radioactive element to decay to 1 g is 304.8 s.
I agree. There can't ever be 2 equal signs in A math problem
Given:
The expression is:
![18\dfrac{2}{5}-4\dfrac{1}{10}](https://tex.z-dn.net/?f=18%5Cdfrac%7B2%7D%7B5%7D-4%5Cdfrac%7B1%7D%7B10%7D)
To find:
The difference.
Solution:
We have,
![18\dfrac{2}{5}-4\dfrac{1}{10}](https://tex.z-dn.net/?f=18%5Cdfrac%7B2%7D%7B5%7D-4%5Cdfrac%7B1%7D%7B10%7D)
It can be rewritten as:
![=\dfrac{90+2}{5}-\dfrac{40+1}{10}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B90%2B2%7D%7B5%7D-%5Cdfrac%7B40%2B1%7D%7B10%7D)
![=\dfrac{92}{5}-\dfrac{41}{10}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B92%7D%7B5%7D-%5Cdfrac%7B41%7D%7B10%7D)
Taking LCM, we get
![=\dfrac{184-41}{10}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B184-41%7D%7B10%7D)
![=\dfrac{143}{10}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B143%7D%7B10%7D)
![=\dfrac{140+3}{10}](https://tex.z-dn.net/?f=%3D%5Cdfrac%7B140%2B3%7D%7B10%7D)
![=14\dfrac{3}{10}](https://tex.z-dn.net/?f=%3D14%5Cdfrac%7B3%7D%7B10%7D)
Therefore, the value of the difference is
.