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beks73 [17]
3 years ago
15

Solve for the quotient 8498 / 70

Mathematics
2 answers:
WINSTONCH [101]3 years ago
5 0

Answer:

121.4 is the answer ❣️

Ivenika [448]3 years ago
3 0

Answer:

The answer I got is 121.4

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Points ), K and L are collinear with J between L and K. IF KJ = 28 - 3, LK = 9x + 7 and LJ = 4x - 8,
babymother [125]

J, K, and L are collinear

J is between K and L

LK = KJ + LJ

LK = 9x + 7

KJ = 2x - 3

LJ = 4x - 8

9x + 7 = (2x - 3) + (4x - 8)

9x + 7 = (2x + 4x) + (-3 - 8)

9x + 7 = 6x + -11

9x + 7 = 6x - 11

9x + 7 - 7 = 6x - 11 - 7

9x = 6x - 18

9x - 6x = 6x - 6x - 18

3x = -18

x = -6

∴ The value of x is -6

6 0
3 years ago
Which number is the LARGEST? -5/6 -3/4 -2/3 -4/5​
Ivanshal [37]

Answer:

-2/3

Step-by-step explanation

3 0
3 years ago
Read 2 more answers
Isaac made a mistake. in his checkbook​
tino4ka555 [31]

Answer:

uh oh. that's never good. is there more to the question lol?

Step-by-step explanation:

please mark brainliest, give a thanks, and rate a five stars if this helped! feel free to ask anymore questions if you need any more help! thanks!

(lol optional): add my sc: tealyn337

8 0
3 years ago
Is 11/16 bigger than 3/4
Goryan [66]
No 3/4 is bigger

if you multiply the top and bottom of 3/4 by 4, you get 12/16.

11/16 <12/16
8 0
3 years ago
Charlie invests £1200 at 3.5% per annum compound interest.
lbvjy [14]

Answer:

<h2>£1,330.46</h2>

Step-by-step explanation:

Using the compound interest formula A = P(1+\frac{r}{n} )^{nt}

A = amount compounded after n years

P = principal (amount invested)

r = rate (in %)

t = time (in years)

n = time used to compound the money

Given P =  £1200., r = 3.5%, t = 3years, n = 1 year(compounded annually)

A = 1200(1+0.035)^{3}\\ A = 1200(1.035)^{3}\\ A = 1200* 1.108717875\\A = 1,330.46

Value of Charlie's investment after 3 years is £1,330.46

6 0
3 years ago
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