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DerKrebs [107]
3 years ago
6

Write the ratio in fractional notation in lowest terms 26 inches to 39 inches

Mathematics
1 answer:
Step2247 [10]3 years ago
8 0
26/39=0.66666 or 2/3 you can divide 26 and 39 by 13 to get the simplified fractions. 2:3
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8/11 of a class of 44 pupils passed their science test. how many pupils failed the test?​
lbvjy [14]

Answer:

12 pupils failed the test

4 0
3 years ago
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The diameter of Mercury is approximately 4.9×103 kilometers. The diameter of Earth is approximately 1.3×104 kilometers. About ho
-Dominant- [34]
Hi there!

To get the answer to this question, let's divide the diameter of the Earth by the diameter of Mercury.

\frac{1.3*10^4}{4.9*10^3}

We can change this to

\frac{1.3}{4.9}*\frac{10^4}{10^3}

Let's solve for each individual fraction

\frac{1.3}{4.9} ≈ 0.27

\frac{10^4}{10^3} = 10

Now, multiply.

0.27 * 10 = 2.7

That's your answer.

Have an awesome day/night! :)

~collinjun0827, Junior Moderator
5 0
3 years ago
a cereal box is 18 inches by 3 inches by 12 inches. After breakfast, the box is one-third full. How many cubic inches of cereal
Nadusha1986 [10]

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Answer: 216 in ^3

Explanation:

18 x 3 x 12 = 648

648 / 3 = 216 in ^3

I hope this helped!

<!> Brainliest is appreciated! <!>

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*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆*――*☆**☆*――*☆*――*☆*――*☆

5 0
3 years ago
Solve 4 cos2x-3 = 0 for all real values of x.
vichka [17]

4 cos² x - 3 = 0

4 cos² x = 3

cos² x = 3/4

cos x = ±(√3)/2

Fixing the squared cosine doesn't discriminate among quadrants.  There's one in every quadrant

cos x = ± cos(π/6)

Let's do plus first.  In general, cos x = cos a has solutions x = ±a + 2πk integer k

cos x = cos(π/6)

x = ±π/6 + 2πk

Minus next.

cos x = -cos(π/6)

cos x = cos(π - π/6)

cos x = cos(5π/6)

x = ±5π/6 + 2πk

We'll write all our solutions as

x = { -5π/6, -π/6, π/6, 5π/6 } + 2πk integer k

3 0
3 years ago
The value of a certain car decreases by 16% each year. What is the 1⁄2-life of the car?
svet-max [94.6K]

Answer:

The half life of the car is 3.98 years.

Step-by-step explanation:

The value of the car after t years is given by the following equation:

V(t) = V(0)(1-r)^{t}

In which V(0) is the initial value and r is the constant decay rate, as a decimal.

The value of a certain car decreases by 16% each year.

This means that r = 0.16

So

V(t) = V(0)(1-r)^{t}

V(t) = V(0)(1-0.16)^{t}

V(t) = V(0)(0.84)^{t}

What is the 1⁄2-life of the car?

This is t for which V(t) = 0.5V(0). So

V(t) = V(0)(0.84)^{t}

0.5V(0) = V(0)(0.84)^{t}

(0.84)^{t} = 0.5

\log{(0.84)^{t}} = \log{0.5}

t\log{0.84} = \log{0.5}

t = \frac{\log{0.5}}{\log{0.84}}

t = 3.98

The half life of the car is 3.98 years.

7 0
3 years ago
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