The table is:0 1 2 3
x1 0 0.08 0.06 0.04 0.00
1 0.05 0.18 0.05 0.03
2 0.05 0.04 0.10 0.06
3 0.00 0.03 0.04 0.07
4 0.00 0.01 0.05 0.06
Expected difference =
+(0.08*(0-0)) +(0.06*(0-1)) +(0.04*(0-2)) +(0.00*(0-3)) +(0.05*(1-0)) +(0.18*(1-1)) +(0.05*(1-2)) +(0.03*(1-3)) +(0.05*(2-0)) +(0.04*(2-1)) +(0.10*(2-2)) +(0.06*(2-3)) +(0.00*(3-0)) +(0.03*(3-1)) +(0.04*(3-2)) +(0.07*(3-3)) +(0.00*(4-0)) +(0.01*(4-1)) +(0.05*(4-2)) +(0.06*(4-3))
= 0.17
Answer:
a = - 5, a = - 3
Step-by-step explanation:
Given
a² + 8a + 15 = 0 ← in standard form
(a + 3)(a + 5) = 0 ← in factored form
Equate each factor to zero and solve for a
a + 3 = 0 ⇒ a = - 3
a + 5 = 0 ⇒ a = - 5
Answer:
158.4 pounds
Step-by-step explanation:
first find the volume of the tank
to convert this to m^3 we know that 1m = 100cm
the cm^3 cancel out.
by simply converting the side-lengths to meters beforehand can give you this answer directly:
it is given that 1 meter cube of water weighs about 2200 pounds.
multiply both sides with 0.072 to find our answer:
hence the weight of the water in the tank would be 158.4 pounds!
Answer:
C
X=-16
Step-by-step explanation:
