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3 years ago

Need help, someone answer! It’s a quiz!

Mathematics

1 answer:

cupoosta [38]3 years ago

5 0

Answer:

i've answered in the comment

Step-by-step explanation:

You might be interested in

Divide 15 in the ratio 2:1 =?

Natalija [7]

2+1=3
15/3=5
split the 3 5's in ratio 2:1 and you get 10:5

3 0

4 years ago

Constant terms or terms that have the same variable raised to the same power is called

aksik [14]

Answer:

"like terms"

Step-by-step explanation:

It looks like you're asking for the word or phrase that has the meaning you have given. Such terms are called <em>like terms</em>.

4 0

3 years ago

After the 4th half life how much of the sample is left if the mass is 100g.

vazorg [7]

Answer:

$\huge\boxed{\sf 6.25 \ g}$

Step-by-step explanation:

After every Half life , Half of the mass is left.

After 1st Half life = 100 g / 2 = 50 g

After 2nd Half life = 50 / 2 = 25 g

After 3rd Half life = 25 / 2 = 12.5 g

After 4th Half life = 12.5 / 2 = 6.25 g

$\rule[225]{225}{2}$

Hope this helped!

6 0

3 years ago

A donut store has 11 different types of donuts. You can only buy a bag of 3 of them, where each donut has to be of a different t

MakcuM [25]

Answer:

$165$ .

Step-by-step explanation:

Since repetition isn't allowed, there would be $11$ choices for the first donut, $(11 - 1) = 10$ choices for the second donut, and $(11 - 2) = 9$ choices for the third donut. If the order in which donuts are placed in the bag matters, there would be $11 \times 10 \times 9$ unique ways to choose a bag of these donuts.

In practice, donuts in the bag are mixed, and the ordering of donuts doesn't matter. The same way of counting would then count every possible mix of three donuts type $3 \times 2 \times 1 = 6$ times.

For example, if a bag includes donut of type $x$ , $y$ , and $z$ , the count $11 \times 10 \times 9$ would include the following $3 \times 2 \times 1$ arrangements:

$xyz$ .
$xzy$ .
$yxz$ .
$yzx$ .
$zxy$ .
$zyx$ .

Thus, when the order of donuts in the bag doesn't matter, it would be necessary to divide the count $11 \times 10 \times 9$ by $3 \times 2 \times 1 = 6$ to find the actual number of donut combinations:

$\begin{aligned} \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

Using combinatorics notations, the answer to this question is the same as the number of ways to choose an unordered set of $3$ objects from a set of $11$ distinct objects:

$\begin{aligned}\begin{pmatrix}11 \\ 3\end{pmatrix} &= \frac{11 !}{(11 - 3)! \times 3 !} \\ &= \frac{11 !}{8 ! \times 3 !} \\ &= \frac{11 \times 10 \times 9}{3 \times 2 \times 1} = 165\end{aligned}$ .

5 0

2 years ago

In order to select new board members, the French club held an election. 50% of the 52 members of the club voted. How many member

kiruha [24]

Answer:

26 Members Voted

Step-by-step explanation:

50 % is 50/100

Voted = $(50/100) X 52 = 52/2 = 26$

3 0

3 years ago

Read 2 more answers