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3 years ago

If you know the y-intercept of a line what else do you need to write it equal

Mathematics

1 answer:

andreev551 [17]3 years ago

4 0

Answer: do you mean, “if you have the y-int, what else do you need to write an equation?”

If that’s what you mean then you need the slope

Step-by-step explanation:

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Arrange these numbers in order from least to greatest 0.1, 1, -1,

LenaWriter [7]

Answer:

-1, 0.1, 1

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3 years ago

Read 2 more answers

Calculate the area of the triangle with the following vertices (3, -7), (6, 4), (-2, -3)

Monica [59]

Answer:

$\boxed{\mathsf{A} \triangle = \red{\dfrac{67}{2}u.a}}$

Step-by-step explanation:

Let's follow up with the solution. Considering a triangle with the vertices $\mathsf{A(x_A, y_A)}$ , $\mathsf{B(x_B, y_B)}$ and $\mathsf{C(x_C, y_C)}$ , have a look at the representation in the cartesian plan.

From this representation we can say that the area (A) of a triangle through the knowledge of <u>analytical geometry</u> is given by the determinant of the vertices divided by two, mathematically,

$\mathsf{A} \triangle = \dfrac{\left| \begin{array}{ccc} \mathsf{x_A} & \mathsf{y_A }& 1 \\ \mathsf{x_B} & \mathsf{ y_B} & 1 \\ \mathsf{ x_C} & \mathsf{ y_C} & 1 \end{array} \right|}{2}$

So, applying this knowledge we're going to have,

$\mathsf{A} \triangle = \dfrac{\left| \begin{array}{ccc} 3 & -7 & 1 \\ 6 & 4 & 1 \\ -2 & -3 & 1 \end{array} \right|}{2}$

$\mathsf{A} \triangle = \dfrac{1}{2}\left[ \left.\begin{array}{ccc} 3 & -7 & 1 \\ 6 & 4 & 1 \\ -2& -3 & 1 \end{array} \right| \begin{array}{cc} 3 & -7 \\ 6 & 4 \\ -2 & -3 \end{array} \right]$

$\mathsf{A} \triangle = \dfrac{12 + 14 - 18 - (-8 - 9 - 42)}{2}$

$\red{\mathsf{A} \triangle = \dfrac{67}{2} = 33,5u.a}$

Hope you enjoy it, see ya!)

$\green{\mathsf{FROM}}:$ Mozambique, Maputo – Matola City – T-3

DavidJunior17

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3 years ago

What are the midline, amplitude, and period of the graphed sine function?

Sunny_sXe [5.5K]

The midline, amplitude and period respectively of the given sine graph are; x = 1; 2; π

<h3>Midline, Amplitude and Period</h3>

The midline of this trigonometric graph is defined as the horizontal line that divides the maximum and minimum point distance into two equal parts. In this case, the midline is x = 1

The amplitude of a graphed function is usually the peak of the wave of that graph. In this case, we see that the peak of the graph is at y = 4. Thus, Amplitude = 4

Period is the difference between two consecutive maximum or minimum points. In this graph, the period is π

Read more about Midline, Amplitude and Period at; brainly.com/question/21124447

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2 years ago

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disa [49]

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3 years ago

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3 years ago