Answer:
Theta has a reference angle of 30° and is in Quadrant I or II
Step-by-step explanation:
Sin(theta) = ½
Basic angle: 30
Angles:
30,
180-30 = 150
Because sin is positive in quadrants 1 and 2
Step-by-step explanation:
you find the blank number by finding the pattern. on number 9 the number increases by 10 every time. you find the mean by adding all the numbers on question 9 and finding the average.
example say its 0 5 10 _ 20 25
you can assume the blank is 15 because the pattern is +5
then you add all of them together which is 75
then you find the average or mean. you find this by dividing it by the numbers you started off with. with this example you divide it by 6 because we started with 6 numbers.
the mean would be 12.5
hope this helped
Well, what I would do [not sure if it's the correct way], is use the white area as a sector of a circle. The top right of the box is the center of the circle, so the radius is 6.
Then, by the white portion being one quarter of the circle (90° out of 360°), I could calculate the that pink shaded region = the total square (6×6) minus the white sector.
So area (A) of white sector (s): A(s) = 1/4×pi×r^2

36 - 28.27 = 7.73
Answer:
The carpenter will not be able to buy 12 '2 by 8 boards' and 14 '4 by 4 boards'.
Step-by-step explanation:
Given:
Amount a carpenter can spend at most = $250
The inequality to represent the amount he can spend on each type of board is given as:

where
represents '2 by 8 boards' and
represents '4 by 4 boards'.
To determine whether the carpenter can buy 12 '2 by 8 boards' and 14 '4 by 4 boards'.
Solution :
In order to check whether the carpenter can buy 12 '2 by 8 boards' and 14 '4 by 4 boards' , we need to plugin the
and
in the given inequality and see if it satisfies the condition or not or in other words (12,14) must be a solution for the inequality.
Plugging in
and
in the given inequality



The above statement can never be true and hence the carpenter will not be able to buy 12 '2 by 8 boards' and 14 '4 by 4 boards'.
<h3 /><h3>

</h3>
Equation for Perimeter of a rectangle: Perimeter = 2W + 2L
<h3>Defining the variables, let</h3>
<h3>Width = x</h3><h3>Length = 2x+3 (3 more than twice the width)</h3>
<h3>Plugging everything into the equation</h3>
<h3>30= 2(x) + 2(2x+3) using the distributive property,</h3>
<h3>30=2x+4x+6 combining like terms</h3>
<h3>30=6x+6 subtracting 6 from both sides,</h3>
<h3>24=6x divide both sides by 6</h3>
<h3>4=x This means that the width is 4 m.</h3>
<h3>To get the length, use the expression L=2x+3 and plug in x = 4 that was already solved for</h3>
<h3>L=2(4)+3</h3>
<h3>L=8+3 = 11 m</h3>
<h3>So the dimensions of the rectangle are width is 4 m and length is 11 m.</h3>