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Ronch [10]
3 years ago
6

Which identity is the result of using the pythagorean theorem to show that a triangle with side lengths x^2 - 1, 2x, and x^2 +

1 is a right triangle?
A. (x^2 - 1)^2 + (2x)^2 = -(x^2 + 1)^2
B. -(x^2 -1)^2 + (2x)^2 = (x^2 +1)^2
C. (x^2-1)^2 + (2x)^2 = (x^2 +1)^2
D. (x^2 - 1)^2 - (2x)^2 = (x^2 + 1)^2
Mathematics
2 answers:
vfiekz [6]3 years ago
8 0

9514 1404 393

Answer:

  C.  (x^2-1)^2 + (2x)^2 = (x^2 +1)^2

Step-by-step explanation:

Inexplicably, three of the four answer choices have minus signs in them. Those are all incorrect. The appropriate choice is ...

  C. (x^2-1)^2 + (2x)^2 = (x^2 +1)^2

__

Expanded, this is ...

  x^4 -2x^2 +1 +4x^2 = x^4 +2x^2 +1 . . . . the desired identity

ella [17]3 years ago
6 0

Answer:

C.  (x^2-1)^2 + (2x)^2 = (x^2 +1)^2

Step-by-step explanation:

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3 years ago
HURRY!!!:) Find the sum of (7x+4) and the opposite of 7x.
jeka57 [31]

Answer:

  • 4

Step-by-step explanation:

<u>Sum of (7x+4) and the opposite of 7x:</u>

  • 7x + 4 + (-7x) =
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7 0
3 years ago
If the operation is defined for all integers a and b by <a href="/cdn-cgi/l/email-protection" class="__cf_email__" data-cfemail=
leva [86]

Answer:

(E) I, II and III

Step-by-step explanation:

Given,

[email protected] = a + b - ab ∀ a, b ∈ Z ( set of all integers ),

For solving this question we need to remember the following properties of integers:

  • Commutative property of addition
  • Additive identity property of addition
  • Commutative property of multiplication
  • Distributive property of multiplication over addition

I. [email protected] = a + b - ab,

[email protected] = b + a - ba = a + b - ab

Thus, [email protected] = [email protected]

II. [email protected] = a + 0 - a × 0

= a + 0 - 0  

= a

III. ([email protected])@c = ([email protected])+c - ([email protected])c

= (a + b - ab) + c - (a + b - ab)c

= a + b - ab + c - ac - bc + abc

= a + b + c - ab - bc - ac + abc,

Now, [email protected]([email protected]) = [email protected]( b + c - bc )

= a + (b + c - bc) - a(b+c - bc)

= a + b + c - bc - ab - ac + abc

= a + b + c - ab - bc - ac + abc.

Thus, ([email protected])@c = [email protected]([email protected])

6 0
3 years ago
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