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hammer [34]
3 years ago
5

What is 7.2199 rounded to the nearest thousandth

Mathematics
2 answers:
frutty [35]3 years ago
5 0
The answer to yiur question is Its 7.220 trust me
Delicious77 [7]3 years ago
4 0
7.2200 is the coreecr answer
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PLEASE HELP ME I AM TAKING A TEST AND I NEED HELP!!!
zhannawk [14.2K]
Part A.
y=4x+3

Part B.
11=4x+3
8=4x
2=x
2 dollars

Part C.
4(3)+4(2)=12+8=20

It would be enough if there is no sales tax.

Hope this helps!
Your fortune is "Only one fortune a day!"
3 0
3 years ago
I need help with letter B, please!
Gala2k [10]

So if you want to fit the y-intercepts or "b", on the y-axis you should go by 25's [0, 25, 50, 75, 100...]

If the x-axis <u>does not have to</u> follow the same pattern (25's), you should go by 5's  [0, 5, 10, 15, 20...]

y = 7x + 50

y = 2x + 175

First I would plot the y-intercepts for each equation, then plot a few points with x = 5, 10, 15      Then draw a straight line.

The point where the two lines meet/cross paths is your solution. It should be (25, 225)  The x-axis is the number of miles, and the y-axis is the total cost. So Truck driver A and B would arrive/be at the same place/meet in 25 miles at the same cost of $225

5 0
3 years ago
Three consecutive intergers have a sum of 84. Find the intergers<br><br> ___,___,___,
Fudgin [204]

Answer:

27 + 28 + 29 = 84

Step-by-step explanation:

x + (x+1) + (x+2) = 84

3x + 3 = 84

84 - 3 = 81

81 / 3 = 27

8 0
4 years ago
If you make $120 in tips after waiting on 6 tables what is you average tip per table?
matrenka [14]
$20 per table, I work at a restaurant haha this is all I hear about
4 0
3 years ago
Read 2 more answers
Grayson ran 2 1/2 miles around the track .each lap is 5/6 of a mile .how many laps did Grayson run?
andrezito [222]

Given:

Number of miles covered = 2\dfrac{1}{2}

Length of each lap = \dfrac{5}{6} of a mile.

To find:

The number of laps.

Solution:

We know that,

\text{Number of laps}=\dfrac{\text{Number of miles covered}}{\text{Length of each lap}}

\text{Number of laps}=\dfrac{2\dfrac{1}{2}}{\dfrac{5}{6}}

\text{Number of laps}=\dfrac{\dfrac{5}{2}}{\dfrac{5}{6}}

\text{Number of laps}=\dfrac{5}{2}\times \dfrac{6}{5}

\text{Number of laps}=3

Therefore, Grayson ran 3 laps.

5 0
2 years ago
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