Y-8/6=7
y-8=7(*6)
y-8=42
y=42(+8)
y=50
The answer is 50.
Answer:
The difference in the populations of the cities when t=4 is 25,800.
Step-by-step explanation:
Given equations each of the city:
-150t+50,000
and
50t+75,000
To find the difference between the population when t=4, we first have to solve both equation when t=4.
For both equations, substitute 4 into t:
-150(4) + 50,000 = 49,400
50(4) + 75,000 = 75,200
Now subtract 49,400 from 75,200 and you get 25,800.
The difference in the populations of the cities when t=4 is 25,800.
Answer:
(3±√147, 0) ≈ (-9.124, 0) and (15.124, 0)
Step-by-step explanation:
The points (x, 0) satisfy the distance formula:
d = 14 = √((x -3)² +(0+7)²)
196 = (x -3)² +49 . . . . . square both sides
147 = (x -3)² . . . . . . . . . subtract 49
3 ±√147 = x . . . . . . . . . take the square root and add 3
The points at distance 14 from (3, -7) on the x-axis are (3±√147, 0).
Answer:
How do we get a bigger number? Subtracting or dividing will just make it smaller. So we have to multiply. We need it about 4 times bigger (3 x 28 = 84, 4 x 28 .
Step-by-step explanation: