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inn [45]
3 years ago
13

Factor f(x)= 2x^4 -12x^3 +6x +20x

Mathematics
1 answer:
leva [86]3 years ago
5 0

Answer:

f(x)= 2x(x^3-6x^2+13)

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Find the volume of a cone with a height of 12 and a base diameter of 6.
vichka [17]

Answer: 466.56

Step-by-step explanation:

Volume = pi times radius^2 times height/3

Radius = 1/2 of the diameter

Volume = 3.24 times 6^2 times 12/3

Volume = 3.24 times 36 times 4

Volume = 116.64 times 4

Volume = 466.56

5 0
2 years ago
One pound of swordfish costs as much as 1.5 pounds of salmon. Mrs. O pays $39 for 2 pounds of salmon and 3 pounds of swordfish.
Dimas [21]

Answer:

The ratio of the amount for swordfish to the amount of salmon is 6:4

Step-by-step explanation:

Given as :

The price for 1 pound of swordfish = The price of 1.5 pound of salmon

So, On this relation

The price for ( 1 × 2 ) pound of swordfish = The price of ( 1.5× 2 )  pound of salmon

i.e The price for 2 pound of swordfish = The price of 3 pound of salmon

Now According to question

Mrs. O pay the total money for 2 pounds of swordfish and 3 pound of salmon = $ 39

Let the money she pay for swordfish = 2 sw

And The money she pay for salmon = 3 sa

∵, The total money she pay for both  = $ 39

I.e  2 sw + 3 sa = 39

As 2 sw = 3 sa

So, 3 sa + 3 sa = 39

Or, 6 sa = 39

or, sa = \frac{39}{6} = \frac{13}{2}

∴ sw = \frac{13}{2} × \frac{3}{2}

or, sw = \frac{39}{4}

Now, the ratio of the amount for swordfish to the amount of salmon = \frac{\frac{39}{4}}{\frac{13}{2}}

I.e The ratio = \frac{6}{4}

Hence The ratio of the amount for swordfish to the amount of salmon is 6:4

Answer

3 0
3 years ago
Need help please help me if you know it
scoundrel [369]

Answer:

I believe it's C... Not sure though...

7 0
3 years ago
Solve the equation. Round the answer to the nearest tenth.
VMariaS [17]
1,04x+3,14=7,98\ \ \  \ \ | subtract\ 3,14\\\\
1,04x=4,84\\\\
x\approx4,7
5 0
3 years ago
Change this radical to an algebraic expression with fractional exponents.
vekshin1

Rational exponents

a^\frac{m}{n}

work like this: the numerator is the actual exponent of the base, while the denominator is the index of the root.

In other words, we have

a^\frac{m}{n}=\sqrt[n]{a^m}

So, in you case, we have

\sqrt[5]{x^3}=x^\frac{3}{5}

Assuming that the question contanis a typo. If you actually mean 5\sqrt{x^3},

then you can write it as 5x^\frac{1}{3}

7 0
4 years ago
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