Answer:
x= -8
Step-by-step explanation:
you combined the two equations to equal 180 since CIA are supplementary and the you solve the equation.
Find out how much you need for one person then multiply by 18 is one way you could do this..
4 divided by 24 = 0.166666666666667 x 18 = 3 litres of lemon-lime soda.
2 divided by 24 = 0.083333333333333 x 18 = 1.5 pints of servet
6 divided by 24 = 0.25 x 18 = 4.5 cups of ice.
Hope this helps!
Your teacher may have wanted you to (some how) use your 6x tables to work this out?!
The length of the sky lift is 3.387.05 ft
Step-by-step explanation;
By an online search, i found that the sky lift
rises at an angle of 20.75 degrees.
Then we can think on a triangle rectangle, such
that:
One cathetus is 1200ft, this is the opposite
cathetus to the angle of 20.75°
The length of the ski lift would be the
hypotenuse of this triangle rectangle.
Then we can use the relationship:
Sin(a) = opposite cathetus/hypoteuse.
such that:
a = 20.75°
opposite cathetus=1200ft
then:
sin(20.75°) = 1200ft/hypotenuse
hypotenuse =1200ft/sin(20.759) =3.387.05 ft
The length of the sky lift is 3.387.05 ft
Answer:
See explanation above
Step-by-step explanation:
This problem is very similar to one I solved a few moments ago. First we need to know how much it rain during the month of august the first 15 days of august. We only know how much it rain from the 15th through the end of the month.
So if you want to know the total rainfall of the month, you only need to sum the amount of the rainfall from the first 15 days of august and the last days of the month.
To help you out, I will use the same data of the other problem, which was 8.33 cm for the first 15 days, and 4.65 for the last 15 days of august.
If you sum 8.33 and 4.65:
8.33 + 4.65 = 12.98 cm
This would be (theorically speaking) the total rainfall during this month. Now, if it's the same exercise that you have, then good, use this answer, but if it's not then, all you need to do is put the value for the first 15 days and do the sum with 4.65 cm to get the total.
