15.58 feets and 18 or 15.5
Answer:
38.5 cm^2
Step-by-step explanation:
Area(shaded) = Area(large semicircle) - area(2 small equal semicircles)
= Area (large semicircle) - area (small circle)
= π(7)² x 1/2 - π(7/2)²
22/7 x 7 x 7 x 1/2 - 22/7 x 7/2 x 7/2
= 77 - 38.5
= 38.5 cm^2
Answer:
Right, Acute, Scalene.
Step-by-step explanation:
12.15 km /h
Step-by-step explanation:
Step 1 :
Given
Distance between Airy Town to Brightvale = 9 km
Speed of Ricky = x km/h
Step 2:
Speed taken by Sam = x + y km/h
Time taken by Sam = 40 min = 40/60 hrs = 2/3 hrs
so we have (x+y) 2/3 = 9
Step 3:
Speed taken by Timothy = x - y km / h
Time taken by Timothy = 50 min = 50/60 = 5/6 hrs
= > (x-y) 5/6 = 9
Step 4 :
Solving the 2 equations
(x+y) 2/3 = 9 and (x-y) 5/6 = 9 we have
(2/3)x + 2/3(y) = 9 = > 2x + 2 y = 27
5/6(x) - 5/6(y) = 9 = > 5 x - 5 y = 54
Multiplying the first equation by 5 and the second by 2 we have ,
10 x + 10 y = 135 and 10 x - 10y = 108
Adding both,
20 x = 243 => x = 12.15.
This gives speed of Ricky as 12.15 km /h
- What is supplementary angle ?
- When sum of two angles is 180°, then each of those two angles will be considered to be the supplementary angle of each other.Example : 150° and 30° are two angles, and their sum is 180°. So, 150° and 30° are supplementary angles.
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<u>Explanation</u> :-
It's given an angle measures 168° more than the measure of its supplementary angle. We are asked to find measure of each angle!
- Let, one of the supplementary angle be "x" . Then the other angle becomes " (x + 168)° "
Sum of these two angles is equal to 180° . Since they are supplementary angles.
![\bf{\underline{\underline{\sf According\ to\ the\ question:-}}}](https://tex.z-dn.net/?f=%20%5Cbf%7B%5Cunderline%7B%5Cunderline%7B%5Csf%20According%5C%20to%5C%20the%5C%20question%3A-%7D%7D%7D%20)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\pink{\bf \twoheadrightarrow {x\ +\ x\ +\ 168^\circ\ =\ 180^\circ} }](https://tex.z-dn.net/?f=%20%5Cpink%7B%5Cbf%20%20%5Ctwoheadrightarrow%20%7Bx%5C%20%2B%5C%20x%5C%20%2B%5C%20168%5E%5Ccirc%5C%20%3D%5C%20180%5E%5Ccirc%7D%20%20%7D)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\sf \twoheadrightarrow 2x + 168^\circ= 180^\circ](https://tex.z-dn.net/?f=%20%5Csf%20%20%5Ctwoheadrightarrow%202x%20%2B%20168%5E%5Ccirc%3D%20180%5E%5Ccirc%20)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\sf \twoheadrightarrow 2x = 180^\circ - 168^\circ](https://tex.z-dn.net/?f=%20%5Csf%20%20%5Ctwoheadrightarrow%202x%20%3D%20180%5E%5Ccirc%20-%20168%5E%5Ccirc%20)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\sf \twoheadrightarrow 2x = 12^\circ](https://tex.z-dn.net/?f=%20%5Csf%20%20%5Ctwoheadrightarrow%202x%20%3D%2012%5E%5Ccirc%20)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\sf \twoheadrightarrow x = \cancel{\dfrac{12^\circ}{2}}](https://tex.z-dn.net/?f=%20%5Csf%20%5Ctwoheadrightarrow%20x%20%3D%20%5Ccancel%7B%5Cdfrac%7B12%5E%5Ccirc%7D%7B2%7D%7D%20)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\pink{\bf \twoheadrightarrow x = 6^\circ }](https://tex.z-dn.net/?f=%20%5Cpink%7B%5Cbf%20%5Ctwoheadrightarrow%20x%20%3D%206%5E%5Ccirc%20%7D)
Then –
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\bf \longrightarrow x +168^\circ](https://tex.z-dn.net/?f=%20%5Cbf%20%20%5Clongrightarrow%20x%20%2B168%5E%5Ccirc)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\tt \longrightarrow 6^\circ+ 168^\circ](https://tex.z-dn.net/?f=%20%5Ctt%20%5Clongrightarrow%20%20%206%5E%5Ccirc%2B%20168%5E%5Ccirc%20)
![\qquad](https://tex.z-dn.net/?f=%5Cqquad)
![\tt \longrightarrow 174^\circ](https://tex.z-dn.net/?f=%20%5Ctt%20%5Clongrightarrow%20174%5E%5Ccirc)
- The measures of the two given angles are 6° and 174°.
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