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ch4aika [34]
3 years ago
13

50 pounds of pet food for $37.99. What is the cost per pound? ( round to the nearest hundredth)

Mathematics
2 answers:
katrin2010 [14]3 years ago
8 0
1 lb of pet food is 76/lb.
oksano4ka [1.4K]3 years ago
6 0

Answer:0.76

Step-by-step explanation:

Divide $37.99÷50=0.759

Round To The Nearest Cent Which Gets You To 0.76

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8 + 12 = 2x<br><br> HELPPPP GOOD ANSWERS
Gennadij [26K]

Answer:

x = 10

Step-by-step explanation:

8 + 12 = 2x

8 + 12 = 20

20 = 2x

----   -----

2      2

10 = x

x = 10

5 0
3 years ago
Read 2 more answers
20. Carmen can buy bottles of paint for $2.00 each and boxes of colored pencils for $3.50 each. She can spend no more than
KIM [24]

Answer:

  (5, 8), (7, 1), (15, 3)

Step-by-step explanation:

a) The variables are defined in the problem statement. The total expenditure must satisfy ...

  2.00x +3.50y ≤ 42.00

b) Possible solutions include ...

 (x, y) ∈ {(5, 8), (7, 1), (15, 3)}

__

These were chosen by looking at the attached graph of the equation.

6 0
3 years ago
5. Joey has $125 to spend on school clothes this year. He only spent $80.00 on school
OLga [1]

Answer:

64%

Step-by-step explanation:

divide 80 by 125 and get .64

7 0
3 years ago
Read 2 more answers
Eleanor and Max used two rectangular pieces of plywood, placed end-to-end, to make a long rectangular stage for the school play.
Flauer [41]

Answer:the width of plywood = 6.25 feet wide or  6 1/4 feet wide

Step-by-step explanation:

Step 1

Area of  a rectangular plywood = length x width

Area of Ist Plywood= 7 x w

Area of 2nd  Plywood= 61/2 x w=6.5 xw

But Total Arae of trhe two Plywoods are = 84 3/8 square feet.

Therefore Our equation to solve the problem becomes

Area of Ist Plywood + Area of 2nd  Plywood =84 3/8 square feet.

7w + 6.5w =  84 3/8

13.5w= 84 3/8

w =  84 3/8/13.5

675/8  / 13.5

w=6.25

Therefore the width of plywood = 6.25 feet wide or 6 1/4 feet.

3 0
3 years ago
Are all squares simular true or false
enyata [817]
ANSWER:
true


STEP-BY-STEP EXPLANATION:
5 0
3 years ago
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