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3 years ago

Please help marking brainlist

Mathematics

2 answers:

Paul [167]3 years ago

7 0

Answer:

-3

Step-by-step explanation:

-3 times 3 equals -9

bekas [8.4K]3 years ago

4 0

Answer:

-3

Step-by-step explanation:

-9/3=-3

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Solve the Differential equation (x^2 + y^2) dx + (x^2 - xy) dy = 0

natita [175]

Answer:

$\frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C$

Step-by-step explanation:

Given differential equation,

$(x^2 + y^2) dx + (x^2 - xy) dy = 0$

$\implies \frac{dy}{dx}=-\frac{x^2 + y^2}{x^2 - xy}----(1)$

Let y = vx

Differentiating with respect to x,

$\frac{dy}{dx}=v+x\frac{dv}{dx}$

From equation (1),

$v+x\frac{dv}{dx}=-\frac{x^2 + (vx)^2}{x^2 - x(vx)}$

$v+x\frac{dv}{dx}=-\frac{x^2 + v^2x^2}{x^2 - vx^2}$

$v+x\frac{dv}{dx}=-\frac{1 + v^2}{1 - v}$

$v+x\frac{dv}{dx}=\frac{1 + v^2}{v-1}$

$x\frac{dv}{dx}=\frac{1 + v^2}{v-1}-v$

$x\frac{dv}{dx}=\frac{1 + v^2-v^2+v}{v-1}$

$x\frac{dv}{dx}=\frac{v+1}{v-1}$

$\frac{v-1}{v+1}dv=\frac{1}{x}dx$

Integrating both sides,

$\int{\frac{v-1}{v+1}}dv=\int{\frac{1}{x}}dx$

$\int{\frac{v-1+1-1}{v+1}}dv=lnx + C$

$\int{1-\frac{2}{v+1}}dv=lnx + C$

$v-2ln(v+1)=lnx+C$

Now, y = vx ⇒ v = y/x

$\implies \frac{y}{x}-2ln(\frac{y}{x}+1)=lnx+C$

5 0

3 years ago

What is the common ratio between successive terms in the sequence?

seropon [69]

Answer:

- 2

Step-by-step explanation:

common ratio is - 2

3 0

3 years ago

A plane can fly 11 miles per minute. The plane will fly 6 trips, and each trip is 500 miles. How many hours will the plane fly?

Kamila [148]

$\frac{500miles}{trip}\times6trips=3000miles$
$\frac{300miles}{\frac{11miles}{minute}}=272.72minue\approx4.54hrs$

4 0

3 years ago

CAN SOMEONE HELP ME PLEASE!!! NUMBER 4 PLEASE HELP THIS IS HOMEWORK! Will mark brainliest!!! (Linear functions btw)

Korolek [52]

Answer:

y = 125x + 500

Step-by-step explanation:

y = mx + b

y = ( (100 - 500) / (2014 - 2010) ) * x + 500

y = (500 / 4) * x + 500

y = 125x + 500

7 0

4 years ago

Use the figure at the right to name the following.

viva [34]

$\large\huge\green{\sf{Answer:-}}$

two acute angle=<JBC and <JBG

<JBC and <JBG(because these two angle are 45°)

by definition of acute angle any angle which is between 0°to 90° then it will acute angle

two straight line=FH ,.AD
two right angle=<GBD and <GBA
two obtuse angle=<BCH and <BGF

6 0

2 years ago