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3 years ago

Draw an example of a composite figure that has a volume between 750 and 900 cubic units

Mathematics

2 answers:

agasfer [191]3 years ago

7 0

A rectangle that is 10 wide and 10 high and 8 units long would have 800 cubic units

Elena L [17]3 years ago

6 0

A three-dimensional figure that will have 8 as a length, 10 as a height, and 10 as width.

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A four sided figure with 90° angles and two sets of opposite sides that are parallel and congruent is called a _________________

kotegsom [21]

I think the answer is rectangle....

Hope this will help u...

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3 years ago

A tree grows three-fourth feet per year. How long will it take the tree to grow from

xenn [34]

Answer:

9 years

Step-by-step explanation:

37-21.25 =15.75ft

1.75ft per year

15.75 / 1.75 = 9 years

4 0

2 years ago

Can anyone help with this?

Karo-lina-s [1.5K]

The answer is B. If you take the even root of a positive number, you'll get two solutions, a positive and a negative

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3 years ago

A ship leaves port at noon and has a bearing of S29oW. The ship sails at 20 knots. How many nautical miles south and how many na

ira [324]

Answer:

Approximately $58.2\; \text{nautical miles}$ (assuming that the bearing is ${\rm S$29^{\circ}$W}$ .)

Step-by-step explanation:

Let $v$ denote the speed of the ship, and let $t$ denote the duration of the trip. The magnitude of the displacement of this ship would be $v\, t$ .

Refer to the diagram attached. The direction ${\rm S$29^{\circ}$W}$ means $29^{\circ}$ west of south. Thus, start with the south direction and turn towards west (clockwise) by $29^{\circ}$ to find the direction of the displacement of the ship.

The hypothenuse of the right triangle in this diagram represents the displacement of the ship, with a length of $v\, t$ . The dashed horizontal line segment represents the distance that the ship has travelled to the west (which this question is asking for.) The angle opposite to that line segment is exactly $29^{\circ}$ .

Since the hypotenuse is of length $v\, t$ , the dashed line segment opposite to the $\theta = 29^{\circ}$ vertex would have a length of:

$\begin{aligned}& \text{opposite (to $\theta$)} \\ =\; & \text{hypotenuse} \times \frac{\text{opposite (to $\theta$)}}{\text{hypotenuse}} \\ =\; & \text{hypotenuse} \times \sin (\theta) \\ =\; & v\, t \, \sin(\theta) \\ =\; & v\, t\, \sin(29^{\circ})\end{aligned}$ .

Substitute in $\begin{aligned} v &= 20\; \frac{\text{nautical mile}}{\text{hour}}\end{aligned}$ and $t = 6\; \text{hour}$ :

$\begin{aligned} & v\, t\, \sin(29^{\circ}) \\ =\; & 20\; \frac{\text{nautical mile}}{\text{hour}} \times 6\; \text{hour} \times \sin(29^{\circ}) \\ \approx\; & 58.2\; \text{nautical mile}\end{aligned}$ .

7 0

2 years ago

What’s the answer to this if u know tho! Thank uuu :)))

alukav5142 [94]

Answer:

180=40+(x+20)

x+20=140

x=120

6 0

3 years ago

Read 2 more answers