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3 years ago

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You went clothes shopping two times. The first time you bought 3 shirts and 2 pants for $120.00. The second time, you paid $213.

00 for 6 shirts and 3 pants. What was the cost for each shirt and for each pair of pants?

1 answer:

attashe74 [19]3 years ago

7 0

Answer:

oh

Step-by-step explanation:

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What are the answers please <br><br><br><br> I will sub and like if you help me please . . .

Alik [6]

Answer:

A: 40

B: 1

C: 4000

Step-by-step explanation:

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3 years ago

1/2,2/5,3/5,3/7 from least to greatest

soldier1979 [14.2K]

your answer would be
2/5, 3/7, 3/5, 1/2

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3 years ago

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Effectus [21]

Simple proportions.

You want a 1:5 ratio.
You have a 5:1 ratio.
So you add another 24 drops of white.
5:25 = 1:5
or
5/x = 1/5 and cross multiply.

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4 years ago

In 2007, the population of Ecuador was estimated at

swat32

Answer:

In 2012 , the population will be 15 million

Step-by-step explanation:

We start by setting up an exponential equation that defines the increase

P(t) = I(1 + r)^t

P(t) represents the present population = 15 million

I is the population in 2007 which is 13.8 million

r is 1.6% = 0.016

t is what we want to calculate

15 million = 13.8 million (1 + 0.016)^t

15/13.8 = (1.016)^t

1.09 = (1.016)^t

ln 1.09 = t ln 1.016

t = ln 1.09/ln 1.016

t = 5.429 which is approximately 5

So in 2007 + 5 = 2012, the population will be 15 million

8 0

3 years ago

*Asymptotes*<br> g(x) =2x+1/x-3 <br><br> Give the domain and x and y intercepts

Nataly [62]

Answer: Assuming the function is $g(x)=\frac{2x+1}{x-3}$ :

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The horizontal asymptote is $y=2$ .

The vertical asymptote is $x=3$ .

Step-by-step explanation:

I'm going to assume the function is: $g(x)=\frac{2x+1}{x-3}$ and not $g(x)=2x+\frac{1}{x}-3$ .

So we are looking at $g(x)=\frac{2x+1}{x-3}$ .

The x-intercept is when y is 0 (when g(x) is 0).

Replace g(x) with 0.

$0=\frac{2x+1}{x-3}$

A fraction is only 0 when it's numerator is 0. You are really just solving:

$0=2x+1$

Subtract 1 on both sides:

$-1=2x$

Divide both sides by 2:

$\frac{-1}{2}=x$

The x-intercept is $(\frac{-1}{2},0)$ .

The y-intercept is when x is 0.

Replace x with 0.

$g(0)=\frac{2(0)+1}{0-3}$

$y=\frac{2(0)+1}{0-3}$

$y=\frac{0+1}{-3}$

$y=\frac{1}{-3}$

$y=-\frac{1}{3}$ .

The y-intercept is $(0,\frac{-1}{3})$ .

The vertical asymptote is when the denominator is 0 without making the top 0 also.

So the deliminator is 0 when x-3=0.

Solve x-3=0.

Add 3 on both sides:

x=3

Plugging 3 into the top gives 2(3)+1=6+1=7.

So we have a vertical asymptote at x=3.

Now let's look at the horizontal asymptote.

I could tell you if the degrees match that the horizontal asymptote is just the leading coefficient of the top over the leading coefficient of the bottom which means are horizontal asymptote is $y=\frac{2}{1}$ . After simplifying you could just say the horizontal asymptote is $y=2$ .

Or!

I could do some division to make it more clear. The way I'm going to do this certain division is rewriting the top in terms of (x-3).

$y=\frac{2x+1}{x-3}=\frac{2(x-3)+7}{x-3}=\frac{2(x-3)}{x-3}+\frac{7}{x-3}$

$y=2+\frac{7}{x-3}$

So you can think it like this what value will y never be here.

7/(x-3) will never be 0 because 7 will never be 0.

So y will never be 2+0=2.

The horizontal asymptote is y=2.

(Disclaimer: There are some functions that will cross over their horizontal asymptote early on.)

6 0

3 years ago