Three inputs have 8 possible states.
Here they are:
0 0 0
0 0 1
0 1 0
0 1 1
1 0 0
1 0 1
1 1 0
1 1 1
Answer:
Devastating Vocal Xcellence
Explanation:
Answer:
I believe it is "Know what you are looking for and carefully filter information for accuracy."
Answer:
#include<iostream>
using namespace std;
int main (){
int n1, n2;
cout<<"Enter 1st number";
cin>>n1;
cout<<"Enter 2nd number";
cin>>n2;
if(n1<n2){
cout<<"The 1st number is the smallest"<<endl<<" is= "<<n1;
}
else{
cout<<"The 2nd number is the smallest"<<endl<<" is= "<<n2;
}
}
return 0;
Answer:
import java.util.Arrays;
import java.util.Scanner;
public class num4 {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.println("How many numbers? ");
int n = in.nextInt();
int []intArray = new int[n];
//Entering the values
for(int i=0; i<intArray.length;i++){
System.out.println("Enter the numbers");
intArray[i]=in.nextInt();
}
System.out.println(Arrays.toString(intArray));
int min =intArray[0];
for(int i =0; i<intArray.length; i++){
if(min>intArray[i]){
min = intArray[i];
}
}
System.out.println("The Minimum of the numbers is "+min);
}
}
Explanation:
- Using Java programming language
- Prompt the user for the number of values
- Using Scanner class receive and store in a variable
- Create an array of size n
- Using an for loop continuously ask the user to enter the integers
- Print the array of integers
- Using another for loop with an if statement, find the smallest element in the array of numbers
- Output the the smallest number
