It is necessary to declare the function as a member of the class that overloads the ->c operator for the class.
<h3>What does C's -> operator mean?</h3>
- In C/C++, the Arrow operator makes it possible to access items in unions and structures.
- It is used in conjunction with a pointer variable pointing to a union or structure.
- As demonstrated below, the arrow operator is created by utilizing a negative sign and the greater than symbol.
- (Pointer name)->(Variable Name) is the syntax.
- To access members of a class, structure, or union using a pointer, use the -> (arrow) operator.
- A member of the object to which the pointer points is designated by a postfix expression, a -> (arrow) operator, followed by a potential qualified identifier or a pseudo-destructor name.
Therefore the correct answer is, c. ->
The complete question is:
The function that overloads the ____ operator for a class must be declared as a member of the class.
a. ::
b. *
c. ->
d. +
To learn more about -> operator, refer to:
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Answer:
C. Grant Access Using Hierarchy sharing setting on the Job Object set to false.
A. "Modify All" permission for Job Object on the Delivery Profile.
E. Organization-Wide Default sharing setting of Private on the Job Object.
Explanation:
In this example, we are dealing with sensitive information. We learn that because of this, the only users who should be able to view and edit job records are the user who owns the record and all users in the delivery profile. In order to protect the information, it is necessary to have an organization-wide default sharing setting of private. After this, we also need the "modify all" permission for job object on the delivery profile and the Grant Access Using Hierarchy sharing setting to be set to false.
Answer:
The output is 24
Explanation:
Given
The above code segment
Required
The output
We have (on the first line):
On the second line:
Substitute the value of each variable
Solve the inner brackets
8%3 implies that, the remainder when 8 is divided by 3.
The remainder is 2
So:
<em>Hence, the output is 24</em>
