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Delicious77 [7]
3 years ago
13

Hello please help me !!!!!

Mathematics
1 answer:
Papessa [141]3 years ago
7 0

Answer:

negative 4 and negative 1

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What is the product of 4 2/7 and 11 1/4 ?
kolbaska11 [484]

Answer:

(4 2/7) x (11 1/4) = 48 3/14

Step-by-step explanation:

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Evaluate the expression (3 • 2) to the second power
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6

Step-by-step explanation:

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For what values of m does the graph of y = 3x2 + 7x + m have two x-intercepts?
frutty [35]

Answer:

m < \frac{49}{12}

Step-by-step explanation:

Using the discriminant Δ = b² - 4ac

Given a quadratic equation in standard form, y = ax² + bx + c

Then the value of the discriminant determines the nature of the roots

• For 2 real roots then b² - 4ac > 0

Given

y = 3x² + 7x + m ← in standard form

with a = 3, b = 7 and c = m, then

7² - (4 × 3 × m) > 0

49 - 12m > 0 ( subtract 49 from both sides )

- 12m > - 49

Divide both sides by - 12, reversing the symbol as a result of dividing by a negative quantity.

m < \frac{49}{12}

8 0
3 years ago
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Dan can tile a floor in 3 hours. his assistant could tile the same floor in 8 hours. if they work together, how long will it tak
natta225 [31]

There is a formula for this:

Total Time = (worker1 * worker2) / (worker1 + worker2)

(3 * 8) / (3 + 8)

24 / 11 =

2.1818181818 hours


7 0
3 years ago
Given that z is inversely proportional to t. When t = 9,z = 28. Find a) the value of z when t = 12 b) the value of t when z = 36
Kazeer [188]

\qquad \qquad \textit{inverse proportional variation} \\\\ \textit{\underline{y} varies inversely with \underline{x}} ~\hspace{6em} \stackrel{\textit{constant of variation}}{y=\cfrac{\stackrel{\downarrow }{k}}{x}~\hfill } \\\\ \textit{\underline{x} varies inversely with }\underline{z^5} ~\hspace{5.5em} \stackrel{\textit{constant of variation}}{x=\cfrac{\stackrel{\downarrow }{k}}{z^5}~\hfill } \\\\[-0.35em] \rule{34em}{0.25pt}

\stackrel{\textit{"z" inversely proportional to "t"}}{z=\cfrac{k}{t}}\qquad \textit{we also know that} \begin{cases} t=9\\ z=28 \end{cases} \\\\\\ 28=\cfrac{k}{9}\implies 252=k~\hfill \boxed{z=\cfrac{252}{t}} \\\\\\ \textit{when t = 12, what is "z"?}\qquad z=\cfrac{252}{12}\implies z=21 \\\\\\ \textit{when z = 36, what is "t"?}\qquad 36=\cfrac{252}{t}\implies t=\cfrac{252}{36}\implies t=7

3 0
2 years ago
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