Answer: The molar volume of any gas at standard pressure and standard temperature is 22.4 liters per mole.
Explanation:The ideal gas law is PV=nRT
P is pressure and if we consider standard pressure, then we have 1.00 atm.
V is volume and that is what we are trying to solve.
n is the number of moles, which is 1.00 moles since we are trying to determine the volume of a gas in one mole.
R is the ideal gas constant which equals
0.0821 (Liters x atmospheres)/(mole x kelvin)
T is the standard temperature which is 273 kelvin.
Rearrange the equation to solve for volume.
V = nRT/P
V = (1.00 mol)(0.0821 L atm/mol K)(273 K)/ 1.00 atm
V = 22.4 L
Answer:
C- Using a 0.35 g sample of Li(s) cut into smaller pieces will increase the rate of reaction
C- Equal quantities of gas will be produced with potassium K, used instead of Lithium, Li.
Explanation:
<u>First part</u>
When a metal is present in small pieces, the rate of the chemical reaction increases. This is due to small pieces provide more surface area for reaction than huge chunks of Li.
moles of reactant decreases product formation rate also decreases and temperature decreases rate also decreases so remaining option are wrong
<u>Second part
</u>
2Li + 2H2O --------------> 2LiOH + H2
2K + 2H2O ---------------> 2KOH + H2
Hence, both gives same quantity of gas
To calculate percent composition, you first need to find the molar mass of C (carbon), H (hydrogen) and O (oxygen).
C is 12.01
H is 1.00
O is 16
Then multiply each by the number of atoms of each element in the formula (the number that comes after each element in the equation for example C6 means 6 carbon atoms.
C: 12.01 x 6= 72.06
H: 1x12= 12
O: 16x6= 96
Then add them up.
72.06+ 12+ 96= 180.06
Now find the percent composition of carbon.
72.06/ 180.06 x 100= 40.01%
So the answer is C 40%.
Answer:
669.48 kJ
Explanation:
According to the question, we are required to determine the heat change involved.
We know that, heat change is given by the formula;
Heat change = Mass × change in temperature × Specific heat
In this case;
Change in temperature = Final temp - initial temp
= 99.7°C - 20°C
= 79.7° C
Mass of water is 2000 g ( 2000 mL × 1 g/mL)
Specific heat of water is 4.2 J/g°C
Therefore;
Heat change = 2000 g × 79.7 °C × 4.2 J/g°C
= 669,480 joules
But, 1 kJ = 1000 J
Therefore, heat change is 669.48 kJ
Answer:
yes, I am pretty sure it can
