Answer:
The initial temperature is 300 K (The temperature doesn't change)
Explanation:
Step 1: Data given
Initial volume = 21L
Final volume = 14L
Initial pressure = 100 kPa = 0.986923 atm
Final pressure = 150 kPa = 1.48038 atm
The final temperature = 300K
Step 2: Calculate the initial temperature
Calculate the initial temperature
(P1*V1)/T1 = (P2*V2)/T2
⇒with P1 = the initial pressure = 0.986923 atm
⇒with V1 = the initial volume = 21 L
⇒ with T1 = the initial temperature = ?
⇒with P2 = the final pressure = 1.48038 atm
⇒with V2 = the final volume = 14 L
⇒with T2 = the final temperature = 300 K
(0.986923 * 21)/T1 = (1.48038*14)/300
T1 = 300 K
The initial temperature is 300 K (The temperature doesn't change)
Answer:
a) Aqueous LiBr = Hydrogen Gas
b) Aqueous AgBr = solid Ag
c) Molten LiBr = solid Li
c) Molten AgBr = Solid Ag
Explanation:
a) Aqueous LiBr
This sample produces Hydrogen gas, because the H+ (conteined in the water) has a reduction potential higher than the Li+ from the salt. Therefore the hydrogen cation will reduce instead of the lithium one and form the gas.
b) Aqueous AgBr
This sample produces Solid Ag, because the Ag+ has a reduction potential higher than the H+ from the water. Therefore the silver cation will reduce instead of the hydrogen one and form the solid.
c) Molten LiBr
In a molten binary salt like LiBr there is only one cation present in the cathod. In this case the Li+, so it will reduce and form solid Li.
c) Molten AgBr
The same as the item above: there is only one cation present in the cathod. In this case the Ag+, so it will reduce and form solid Ag.
Answer:
The new volume will be 3.67 L.
Explanation:
As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide with them fewer times per unit of time. This means that the pressure will be lower because it represents the frequency of collisions of the gas against the walls. In this way pressure and volume are related, determining Boyle's law which says:
"The volume occupied by a certain gaseous mass at constant temperature is inversely proportional to pressure"
Boyle's law is expressed mathematically as:
P*V=k
Now it is possible to assume that you have a certain volume of gas V1 that is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and it will be fulfilled:
P1 * V1 = P2 * V2
In this case:
- P1= 1.85 atm
- V1= 4.64 L
- P2= 2.34 atm
- V2= ?
Replacing:
1.85 atm* 4.64 L= 2.34 atm* V2
Solving:
V2= 3.67 L
<u><em>The new volume will be 3.67 L.</em></u>
Answer:
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Explanation:
