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Y_Kistochka [10]
3 years ago
9

Question 4 (4 points)

Chemistry
1 answer:
Fiesta28 [93]3 years ago
7 0
I don’t know what is your problem
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Name the following:<br> Simple chemical molecules made of single unit
Stolb23 [73]

Answer:

atom is the answer I think

7 0
3 years ago
All of the following are equal to Avogadro's number EXCEPT ____. a. the number of atoms of bromine in 1 mol Br2 b. the number of
Colt1911 [192]

All the following are equal to Avogadro's number EXCEPT a. the number of atoms of bromine in 1 mol Br₂.

1 mol Br₂ contains Avogadro’s number of molecules of Br₂.

However, each molecule contains two atoms of Br, so there are

<em>2 × Avogadro’s number of Br atoms </em>in 1 mol Br₂.

8 0
3 years ago
What volume of solution gives the desired moles?
motikmotik

Answer:

1. 0.073L

2. 0.028L

3. 0.014L

Explanation:

The volume for the different solutions are obtained as shown below:

1. Mole = 0.53mol

Molarity = 7.25M

Volume =?

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 0.53/7.25

Volume = 0.073L

2. 0.035mol from a 1.25M

Mole = 0. 035mol

Molarity = 1.25M

Volume =?

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 0.035/1.25

Volume = 0.028L

3. Mole = 0.0013mol

Molarity = 0.090M

Volume =?

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 0.0013/0.090

Volume = 0.014L

8 0
3 years ago
What is the mass of 0.100 mole of neon? (Watch sf’s) 2.018 g 20.18 g 2.02 g 2 g
makkiz [27]

Answer:

The mass of 0.100 mole of neon is 2.018 grams.

Explanation:

As we know the formula to find mass:

                           Number of moles         =  Mass/ Molar mass

                                        0.100                = Mass/ 20.17

                                        0.100 x 20.17   = Mass

                                                        Mass=2.018 grams.

Hope it helps!

7 0
3 years ago
What is the molarity of a solution made from 325.4 g of AlCl3 (MM 133.34 g/mol) to make 500.0 mL?
NISA [10]

Answer : The molarity of a solution is, 4.88 M

Explanation : Given,

Mass of AlCl_3 = 325.4 g

Volume of solution = 500.0 mL

Molar mass of AlCl_3 = 133.34 g/mole

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Mass of }AlCl_3\times 1000}{\text{Molar mass of }AlCl_3\times \text{Volume of solution (in mL)}}

Now put all the given values in this formula, we get:

\text{Molarity}=\frac{325.4g\times 1000}{133.34g/mole\times 500.0mL}=4.88mole/L=4.88M

Therefore, the molarity of a solution is, 4.88 M

6 0
3 years ago
Read 2 more answers
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