SOMEBODY PLEASE HELP ME. ANSWER THIS QUESTION RIGHT.Use the quadratic equation x^2+10x+38=4 to complete the following statement
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Which parabola?
Equation of the parabola
y - y1 = 4p(x - x1)
The Vertex of the parabola given is (0, 0) because it does not have the values of x1 and y1.
Then Vertex = (0,0)
-Look for two values of y to the left and two points to the right.
You can choose the points that you which
x y
-3 y = -(-3)^2 = -9
-1 y = -(-1)^2 = -1
0 y = -(0)^2 = 0
1 y = -(1)^2 = -1
3 y = -(3)^2 = -9
