Answer:
<h3>The area of the given rectangle increasing when l=20cm and w=25 cm by fast is

</h3>
Step-by-step explanation:
Given that the length of a rectangle is increasing at a rate of 8cm per s and its width is increasing at a rate of 5cm per s.
<h3>To find the how fast is the area of the rectangle increasing when the length is 20 cm and the width is 25 cm:</h3>
Let l be the Length of Rectangle (cm)
Let w be the Width of Rectangle (cm)
Let A be the Area of Rectangle (
)
Let t be the Time (s)
From the given we can write
cm per s and
cm per s
The formula for Area of the rectangle is:
A=lw square units
Differentiating with respect to t
( by using the product rule formula
)

when l=20 and w=25



∴ 
<h3>∴ the area of the rectangle increasing by fast is

</h3>
The answer is f(x)= √ 9-x^2 (option number three). I hope this helps :)
128 over 10 because this as a fraction is 12 and 8/10 so then times 12 by 10 and you get 120 then add 8 and then you get 128 and put it over 10

Actually Welcome to the Concept of the Equations.

1.) Polynomial ==> Binomial
2.) Degree ==> 2
3.) Terms ==> 2
4.) Name ==> Quadratic Equation in two variables.
5.) Coefficient => 7 and 3
Answer: 2/5m - 1/5
Step-by-step explanation:
2(1/5m - 2/5) + 3/5
2/5m - 4/5 + 3/5
2/5m - 1/5