Question

What is the absolute value of the complex number -4-√2i?

Answer 1

Answer-

The absolute value of the complex number is $3\sqrt2$

Solution-

The given complex number is,

$=-4-\sqrt2i$

The absolute value or modulus of a complex number a+bi, is defined as the distance between the origin (0,0) and the point (a,b) in the complex plane.

Its value is calculated by,

$|a+bi|=\sqrt{a^2+b^2}$

So,

$|-4-\sqrt2i|\\\\=\sqrt{(-4)^2+(-\sqrt2)^2}\\\\=\sqrt{16+2}\\\\=\sqrt{18}\\\\=3\sqrt2$

Answer 2

Hello : 
| -4-√2i | = √((-4)² +(-√2)²) =√(16+2) =√18 = √(9×2) = √9 × √2 = 3√2.. (answer B)