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SOVA2 [1]
3 years ago
11

Is ABC ~ DEF? Explain.

Mathematics
1 answer:
Ainat [17]3 years ago
5 0

Answer:

All of the angles are congruent in both triangles

Step-by-step explanation:

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Please help me asappppppppp i will give a brainlest
FromTheMoon [43]

Answer:

No, she is wrong. Look at the coordinates on function A. They don't match up.

4 0
3 years ago
How much money will Gregory donate if the students read 325 books this summer? show your work he will donate 5$ for every book
Anna11 [10]
To solve this multiply the number of books(325) by how much he will donate per book ($5)
325*5=$1625

7 0
4 years ago
Rectangle GHIJ inscribed in a circle, GK⊥JH, GK = 6cm, m∠GHJ = 15°. Find the radius of the circle. pls help !!
Mariulka [41]

Answer:

6(2 + √3)  

Step-by-step explanation:

Given : Rectangle GHIJ inscribed in a circle. <em>GK⊥JH</em>, <em>GK</em> =  6 cm and <em>m∠GHJ</em>=15°.

To find: Radius<em>(KH)</em> =?

Sol:  As given in figure 1, Since <em>GK⊥JH ∴ m∠GKH = 90° . Let GK = x cm.</em>

Now, In ΔGKH,

tan\Theta =\frac{perpendicular}{base}

tan\Theta =\frac{GK}{KH}

tan 15^{\circ} =\frac{6}{x}  

2-\sqrt{3} =\frac{6}{x}         (∵<em> tan 15°</em> = 2 - √3)

x = \frac{6}{2-\sqrt{3} }

On rationalizing the above expression,

x = \frac{6}{2-\sqrt{3} } \times \frac{2+\sqrt{3} }{2+\sqrt{3} } =\frac{6(2+\sqrt{3} )}{4-3}

Therefore, radius of the circle <em>(KH)</em> = 6 (2+√3)

This is how to find the value of <em>tan 15°</em>

<em>tan</em> 15° = <em>tan </em>(45° -30°)

Now using,

tan(A-B) = \frac{tanA-tanB}{1+tanA tanB}

tan(45^{\circ} - 30^{\circ}) = \frac{tan 45^{\circ}-tan30^{\circ}}{1+tan 45 tan30}

tan(45^{\circ} - 30^{\circ}) = \frac{1-\frac{1}{\sqrt{3}}}{1+1\times \frac{1}{\sqrt{3}}}=\frac{\sqrt{3}-1}{\sqrt{3}+1}

On rationalizing,

tan 15^{\circ} = \frac{\left (\sqrt{3}-1 \right )^{2}}{3-1} =\frac{4-2\sqrt{3}}{2}

Taking 2 common from numerator,

<em>tan</em> 15° = 2 - √3

5 0
3 years ago
Read 2 more answers
Pls help. need explanation too pls
FrozenT [24]

Answer:

  • -3 ≤ x ≤ 13

Step-by-step explanation:

<u>Values on x- axis between -3 and 13 both numbers included:</u>

  • x = [-3, 13]
  • -3 ≤ x ≤ 13
5 0
3 years ago
Can you explain what went wrong and the actual answers these 3
vlada-n [284]
For the first one, they got rid of the 6x when they shouldn’t have, and the correct answer is x = 21.5


For the second one, 47 would be subtracted by 180, not 90, and the correct answer is 133


For the third one, 5x - 10 doesn’t equal 115, 5x - 10 equals 180 - 115, and the correct answer is x = 17
7 0
3 years ago
Read 2 more answers
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