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ahrayia [7]
3 years ago
14

Write "twenty-four and seventy thousandths" using base-ten numerals.

Mathematics
1 answer:
aniked [119]3 years ago
4 0

Answer:

24.070

Step-by-step explanation:

twenty-four and seventy thousandths

24

and means change from integers to fractions

24 70/1000

or as a decimal

24.070

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balu736 [363]

Answer:

the answers are options 1, 2, and 5.

3 0
3 years ago
Consider the sequence of steps to solve the equation:
pav-90 [236]

Answer:

Division Property of Equality

Step-by-step explanation:

→In Step 4, it is shown that the equation is:

3x = 30

→However, to solve for x, you must get it by itself. This means you need to get rid of the 3 that's being multiplied. So since the 3 is being multiplied to x, you must do the opposite of multiplication, which is division.

→As you can see, the total of 30 is decreased in Step 5, since it has been divided by 3, giving you a total of 10.

This shows that the property of equality that yields Step 5 is the <u>Division Property of Equality.</u>

4 0
2 years ago
Pls help it is due today!!!!!
Aleksandr [31]

Answer:

BRUH THIS WAS ON MY TEST AND BRUH HONESTLY I HAVE NO CLUEE

8 0
2 years ago
Read 2 more answers
The diagram below represents a generic right triangle.
Oksi-84 [34.3K]
Bshould be the answer !
4 0
3 years ago
While conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modem
Kitty [74]

Answer:

We conclude that this is an unusually high number of faulty modems.

Step-by-step explanation:

We are given that while conducting a test of modems being manufactured, it is found that 10 modems were faulty out of a random sample of 367 modems.

The probability of obtaining this many bad modems (or more), under the assumptions of typical manufacturing flaws would be 0.013.

Let p = <em><u>population proportion</u></em>.

So, Null Hypothesis, H_0 : p = 0.013      {means that this is an unusually 0.013 proportion of faulty modems}

Alternate Hypothesis, H_A : p > 0.013      {means that this is an unusually high number of faulty modems}

The test statistics that would be used here <u>One-sample z-test</u> for proportions;

                             T.S. =  \frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }  ~  N(0,1)

where, \hat p = sample proportion faulty modems= \frac{10}{367} = 0.027

           n = sample of modems = 367

So, <u><em>the test statistics</em></u>  =  \frac{0.027-0.013}{\sqrt{\frac{0.013(1-0.013)}{367} } }

                                     =  2.367

The value of z-test statistics is 2.367.

Since, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the z table gives a critical value of 1.645 for the right-tailed test.</u>

Since our test statistics is more than the critical value of z as 2.367 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which <u><em>we reject our null hypothesis</em></u>.

Therefore, we conclude that this is an unusually high number of faulty modems.

6 0
3 years ago
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